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Stells [14]
3 years ago
11

The green bars are called "error bars." They indicate the range of uncertainty that scientists have about the data on the graph.

(Note: Not all error bars are shown.)
Why do you think these error bars are smaller near the year 2000 than in the 1890s?

Physics
2 answers:
Scilla [17]3 years ago
7 0

Error bars are used to show the error in a reported measurement. The reason why the error bars are smaller near the year 2000 than in the 1890s because the ways of measuring have changed majorly over the past 100 years. The ways of measuring 100 years ago were probably not as accurate as the ways of measuring today.

Best of Luck!

vovangra [49]3 years ago
4 0

This graph shows data up to about 2010. So it couldn't have been drawn before 2010. OF COURSE the data from only 10 years earlier was more reliable than the data that was 120 years old ! It wasn't even measured the same way back then as it is now.

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A 53.3 kg woman slides down a 35.0° hill with an acceleration of 4.10 m/s. What is the friction force acting on the woman?
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Answer:

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Explanation:

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4 0
3 years ago
Which force causes all objects with mass to attract one another?
Scrat [10]
Gravitational force
5 0
3 years ago
two teams are playing tug of war. team a pulls to the right with a force of 450n .team b pulls to the left with a force of 415 n
Alex_Xolod [135]

Explanation:

It is given that, two teams are playing tug of war.

Force applied by Team A, F_A=450\ N

Force applied by Team B, F_B=415\ N

We need to find the net force acting on the rope. It is equal to :

F_{net}=F_A-F_B

F_{net}=450-415

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4 0
3 years ago
Find the magnitude of the sum
shusha [124]

Answer:

\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m

Explanation:

<u>Sum of Vectors in the Plane</u>

Given two vectors

\displaystyle \vec{v_1}\ ,\ \vec{v_2}

They can be expressed in their rectangular components as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_2}=

The sum of both vectors can be done by adding individually its components

\displaystyle \vec{v_1}+\vec{v_2}=

If the vectors are given as a magnitude and an angle (M\ ,\ \theta ), each component can be found as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_2}=

The first vector has a magnitude of 3.14 m and an angle of 30°, so

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=

The second vector has a magnitude of 2.71 m and an angle of -60°, so

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=

The sum of the vectors is

\displaystyle \vec{v_1}+\vec{v_2}=

\displaystyle \vec{v_1}-\vec{v_2}=

Finally, we compute the magnitude of the sum

\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{(4.08)^2+(-0.78)^2}

\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{17.25}

\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m

3 0
3 years ago
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