1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Stells [14]
3 years ago
11

The green bars are called "error bars." They indicate the range of uncertainty that scientists have about the data on the graph.

(Note: Not all error bars are shown.)
Why do you think these error bars are smaller near the year 2000 than in the 1890s?

Physics
2 answers:
Scilla [17]3 years ago
7 0

Error bars are used to show the error in a reported measurement. The reason why the error bars are smaller near the year 2000 than in the 1890s because the ways of measuring have changed majorly over the past 100 years. The ways of measuring 100 years ago were probably not as accurate as the ways of measuring today.

Best of Luck!

vovangra [49]3 years ago
4 0

This graph shows data up to about 2010. So it couldn't have been drawn before 2010. OF COURSE the data from only 10 years earlier was more reliable than the data that was 120 years old ! It wasn't even measured the same way back then as it is now.

You might be interested in
The gravitational force between a satellite and Earth’s moon is 324 N. The mass of the moon is 7.3 × 1022 kg.
tiny-mole [99]

450 kg is your answer middle school physic


8 0
3 years ago
Read 2 more answers
A gas undergoes two processes. In the first, the volume remains constant at 0.200 m3 and the pressure increases from 1.00×105 Pa
Alborosie
<h2>The work done = - 2 x 10⁴ J</h2>

Explanation:

In the first case , the volume is kept constant and pressure varies .

In isothermal process  , the work done

W₁ = V x ΔP

here V is the volume of gas and ΔP is the change in pressure

Thus W₁ = 0

Because there is no change in volume , therefore displacement is zero .

In second case pressure is constant , but volume changes

Thus W₂ = P x ΔV

here P is the pressure  and ΔV is the change in volume

Therefore W₂ = 4 x 10⁵ x 5 x 10⁻² = 2 x 10⁴ J

The total work done W = - 2 x 10⁴ J

Because the work done in compression is negative .

7 0
4 years ago
Which is equal to a temperature of 20°C? <br>20°F <br>68°F<br>36°F <br>32°F
Dahasolnce [82]
The correct answer would be 68°F because (20°C × 9/5) + 32 = 68°F.
4 0
4 years ago
Read 2 more answers
A beam of 1.0 MHz ultrasound begins with an intensity of 1000 W/m². After traveling 12 cm through tissue with no significant ref
Ksenya-84 [330]

Answer:

Option C

Explanation:

Given:

- Depth of tissue d = 12 cm

- frequency of ultrasound f = 1 MHz

- Input Intensity I_i = 1000 W/m^2

- attenuation coefficient soft tissue a = 0.54

Find:

- Out-put intensity at the required depth

Solution

- The amount of attenuation in (dB) with the progression of depth is given by:

                                     Attenuation = a*f*d

                                     Attenuation = 0.54*12*1

                                     Attenuation = 6.48 dB

- The relation with attenuation and ratio of input and output intensity is given by:

                                     Attenuation = 10*log_10 (I_i / I_o)

                                     6.48 dB = 10*log_10 (I_i / I_o)

                                      I_i / I_o = 10^(0.648)

                                      I_o = 1000 / 10^(0.648)

                                      I_o = 225 W/m^2

- Hence the answer is option C:  I_o = 250 W/m^2  

4 0
4 years ago
Two identical soccer balls are rolled toward each other. What will be true after they collide headon? (2 points)
elixir [45]

Complete Question:

Two identical soccer balls are rolled toward each other. What will be true after they collide headon?

Group of answer choices.

A. they will both stop rolling immediately after they collide head–on.

B. One ball will stop rolling and the other will roll backward at a slower speed.

C. They will both roll back at the same speed they had before the collision

D.They will both roll to the side at a faster speed after the collision

Answer:

C. They will both roll back at the same speed they had before the collision

Explanation:

Newton's Third Law of Motion which states that, for every action there is an equal but opposite reaction.

This ultimately implies that, in every interaction, there is a pair of forces acting on the two interacting objects.

In this scenario, two identical soccer balls are rolled toward each other. Thus, after they collide headon, they will both roll back at the same speed they had before the collision in accordance with Newton’s Third Law of Motion.

Additionally, The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.

This ultimately implies that, if the two identical soccer balls exert forces only on each other, their total momentum is conserved

5 0
3 years ago
Other questions:
  • Can someone explain and slove question 4
    6·1 answer
  • Antti entered a 10-kilometer race. His goal is to finish in one hour. He starts off sprinting, and completes the first 2 kilomet
    10·1 answer
  • A 17 kg box sitting on a shelf has a potential energy of 350 J. How high is the shelf? Round your answer to the nearest whole nu
    7·2 answers
  • a fan acquires a speed of 180 rpm in 4s, starting from rest. calculate the speed of the fan at the end of the 5th second startin
    7·1 answer
  • A diagram of a closed circuit with power source on the left labeled 12 V, a resistor on the top labeled 10 Ohms, a resistor on t
    9·2 answers
  • What is the mass of an object that requires a force of 182 N to accelerate at a rate of 13 m/s?
    8·1 answer
  • A block of mass m=3.0 kg is pushed down a 50° incline surface with a force of magnitude F=40 N.
    15·1 answer
  • *PLEASE HELP*
    14·2 answers
  • After today i might not be here no more
    6·2 answers
  • What is the approximate speed of sound in air in metres per second?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!