A. logic, would be your answer i believe!
K= (1/2) m v^2
so 0.5*0.145*<span>1281.64=92.92J of KE</span>
Answer:
They will both bounce back at the same speed they had before the collision
Explanation:
Assuming an elastic collision, kinetic energy will be conserved. Therefore, the billiard balls will have the same speed after the collision as before the collision.
Answer:
The acceleration of the car is 7.85 m/s²
Explanation:
Given;
vx(t)= (0.910m/s³)t², given time traveled by the car 't' = 5.0 s
⇒To determine the velocity for 5 seconds, we substitute in 5.0 s for t
vx(5)= (0.910m/s³)(5s)²
= (0.910m/s³)(25s²)
vx = 22.75 m/s
⇒To determine the acceleration of the car when vx=12.0m/s
Acceleration is change in velocity per unit time
when vx=12.0m/s, our new equation becomes; 12 = (0.910m/s³)t²
Solving for t: t² = 12/0.91
t² = 13.187
t = √13.187 = 3.63 s
Acceleration = Δv/Δt
Acceleration = 7.85 m/s²