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vampirchik [111]
3 years ago
13

Define the terms ‘latent heat of vaporization’ and ‘phase change’ in your own words. What is the commonly accepted value of the

latent heat of vaporization of liquid nitrogen (sometimes written LN2) in J/g? Look this up anywhere, and indicate your source of information
Physics
1 answer:
olganol [36]3 years ago
7 0

Answer:

Latent Heat of Vaporization of Nitrogen is 2.7928 KJmol^{-1}

Explanation:

• We have learned that adding thermal energy by heat increases the temperature of a substance.

• But surprisingly, there are situations where adding energy does not change the temperature of a substance at all. Instead, the additional thermal energy acts to loosen bonds between molecules or atoms and causes a phase change.

• Because this energy enters or leaves a system during a phase change without causing a temperature change in the system, it is known as latent heat (latent means hidden).

• Latent heat of vaporization is a physical property of a substance.

• It is defined as the heat required to change one mole of liquid at its boiling point under standard atmospheric pressure. It is expressed as kg/mol or kJ/kg.

• When a material in liquid state is given energy, it changes its phase from liquid to vapor; the energy absorbed in this process is called heat of vaporization.

• Latent Heat of Vaporization of Nitrogen is 2.7928 KJmol^{-1}

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4 0
3 years ago
When a voltage difference is applied to a piece of metal wire, a 5.0 mA current flows through it. If this metal wire is now repl
zheka24 [161]

Answer:

I = 21.13 mA ≈ 21 mA

Explanation:

If

I₁ = 5 mA

L₁ = L₂ = L

V₁ = V₂ = V

ρ₁ = 1.68*10⁻⁸ Ohm-m

ρ₂ = 1.59*10⁻⁸ Ohm-m

D₁ = D

D₂ = 2D

S₁ = 0.25*π*D²

S₂ = 0.25*π*(2*D)² = π*D²

If we apply the equation

R = ρ*L / S

where (using Ohm's Law):

R = V / I

we have

V / I = ρ*L / S

If V and L are the same

V / L =  ρ*I / S

then

(V / L)₁ = (V / L)₂  ⇒     ρ₁*I₁ / S₁ = ρ₂*I₂ / S₂

If

S₁ = 0.25*π*D²   and

S₂ = 0.25*π*(2*D)² = π*D²

we have

ρ₁*I₁ / (0.25*π*D²) = ρ₂*I₂ / (π*D²)

⇒    I₂ = 4*ρ₁*I₁ / ρ₂

⇒     I₂ = 4*1.68*10⁻⁸ Ohm-m*5 mA / 1.59*10⁻⁸ Ohm-m

⇒     I₂ = 21.13 mA

5 0
3 years ago
Two objects are placed in thermal contact and are allowed to come to equilibrium in isolation. The heat capacity of Object A is
Oksi-84 [34.3K]

Answer:

Explanation:

Heat capacity A = 3 x heat capacity of B

initial temperature of A = 2 x initial temperature of B

TA = 2 TB

Let T be the final temperature of the system

Heat lost by A is equal to the heat gained by B

mass of A x specific heat of A x (TA - T) = mass of B x specific heat of B x ( T - TB)

heat capacity of A x ( TA - T) = heat capacity of B x ( T - TB)

3 x heat capacity of B x ( TA - T) = heat capacity of B x ( T - TB)

3 TA - 3 T = T - TB

6 TB + TB = 4 T

T = 1.75 TB

8 0
3 years ago
If you run 10 km east and then turn around and run 7 km west, how much total distance have you travelled? A. 17 km B. 70 km C. 3
Tom [10]

It's A 17 km because the total km walked is 17.

4 0
3 years ago
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Density is a property of matter that relates
tiny-mole [99]
Density is the mass of a substance per unit volume.
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3 years ago
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