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vampirchik [111]
3 years ago
13

Define the terms ‘latent heat of vaporization’ and ‘phase change’ in your own words. What is the commonly accepted value of the

latent heat of vaporization of liquid nitrogen (sometimes written LN2) in J/g? Look this up anywhere, and indicate your source of information
Physics
1 answer:
olganol [36]3 years ago
7 0

Answer:

Latent Heat of Vaporization of Nitrogen is 2.7928 KJmol^{-1}

Explanation:

• We have learned that adding thermal energy by heat increases the temperature of a substance.

• But surprisingly, there are situations where adding energy does not change the temperature of a substance at all. Instead, the additional thermal energy acts to loosen bonds between molecules or atoms and causes a phase change.

• Because this energy enters or leaves a system during a phase change without causing a temperature change in the system, it is known as latent heat (latent means hidden).

• Latent heat of vaporization is a physical property of a substance.

• It is defined as the heat required to change one mole of liquid at its boiling point under standard atmospheric pressure. It is expressed as kg/mol or kJ/kg.

• When a material in liquid state is given energy, it changes its phase from liquid to vapor; the energy absorbed in this process is called heat of vaporization.

• Latent Heat of Vaporization of Nitrogen is 2.7928 KJmol^{-1}

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The bob (weight) at the end of a pendulum has a mass of 0.3 kilograms. The bob is pulled to position B and allowed to swing. It
Ivahew [28]

Answer:

0.147 J

Explanation:

The total energy that has been transformed into thermal energy is equal to the loss of gravitational potential energy between the initial situation (bob at h=0.5 m above the ground) and the final situation (bob back but at h=0.45 m above the ground).

Therefore, we have

E_{thermal}=\Delta U=mgh_1 - mgh_2 = mg(h_1 -h_2)

where

m = 0.3 kg is the mass of the bob

g = 9.8 m/s^2

h1 = 0.5 m is the initial height

h2 = 0.45 m is the final height

Substituting, we find the thermal energy

E_{thermal}=(0.3 kg)(9.8 m/s^2)(0.5 m-0.45 m)=0.147 J

Therefore, the energy transformed into thermal energy is 0.147 J.

3 0
3 years ago
Ralphie runs north 0.5 km, then turns east and runs 2.0 km, turns south and runs 1.5 km, turns west and runs another 1km. What i
Step2247 [10]

Answer:

I think its 2km

Explanation:

bc if u put it out on a graph, it would essentially take about 4 jumps to get to your ending point, and assuming each jumb was 0.5 km. But if u dont trust me look at another answer bc I dont know if thats right or not.

7 0
3 years ago
What happens to the electrons when you rub a balloon in your hair
777dan777 [17]

Answer:

When you rub a balloon on your head, electrons move from the atoms and molecules in your hair onto the balloon. Electrons have a negative charge, so the balloon becomes negatively charged, and your hair is left with a positive charge.

Explanation:

6 0
3 years ago
A book is sitting on a shelf. Unless someone picks it up or something knocks it off, it will continue to sit there. This is beca
olga_2 [115]
Newton's 1st law of Motion

8 0
3 years ago
Read 2 more answers
Q¹=0,07Mc Q²=2C r=1,08 cm F=.......?
Nostrana [21]
The force (F) of attraction or repulsion between two point charges (Q1 and Q2) is given by the following rule:
F = <span>(k * q1 * q2) / (r^2)  where:
</span>q1 and q2 are the charges
k is coulomb's constant = 9 x 10^9<span> N. m</span>2/ C<span>2
</span>r is the distance between the two charges.

Applying the givens in the mentioned equation, we find that:
F = (9 x 10^9<span> x 0.07 x 10^6 x 2) / (0.0108)^2 = 1.08 x 10^19 n </span> 
5 0
3 years ago
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