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Answer: 0.24 moles
Explanation: Using IDEAL GAS LAW
PV=nRT
where,
P = pressure of the gas= 2.0 atm
V = volume of the gas= 3.00L
T =Temperature of gas=25^0C=(25+273)K=298K
n = number of moles of gas=?
R = Gas constant = 0.0821 Latm/moleK
n=\frac {PV}{RT}=\frac {2.0\times 3.0}{0.0821\times 298}=0.24moles
Answer:
V is proportional to StartFraction n over p EndFraction.
Explanation:
Let us remind ourselves of the statements of both Boyle's law and Avogadro's laws.
Boyle's law states that, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.
Avogadro's law states that at the same temperature and pressure, equal volumes of gases contain equal number of molecules.
Hence ;
V α 1/P (Boyle's law)
V α n (Avogadro's law)
V α n/p (combination of Boyle's law and Avogadro's law)
Explanation:
Question 1
Rate constant = 3.50×10−3 s−1
Initial Concentration [A]o = 0.450 M
Final concentration [A] = ?
time = 19 minutes = 1140 s (upon conversion to seconds)
Integrated rate law for a first order reaction is given as;
ln[A] = ln[A]o - kt
ln[A] = ln (0.450) - (3.50×10−3)1140
ln[A] = -0.799 - 3.99
ln[A] = -4.789
[A] = 0.0083M
Question 2
Rate constant, k = 3.50×10−4 M/s
time = 65 s
Final Concentration [A] = 3.50×10−2 M
Initial Concentration [A]o = ?
Integrated rate law for a first order reaction is given as;
[A] = [A]o - kt
[A]o = [A] + kt
[A]o = 3.50×10−2 + (3.50×10−4) * 65
[A]o = 3.50×10−2 + 0.02275
[A]o = 0.05775 M