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Alika [10]
3 years ago
8

The spring of a toy car stores 10 J of potential energy. Only 8 J of energy changes to kinetic energy as the car moves. What hap

pens to the remaining 2 J of energy?
Physics
1 answer:
FromTheMoon [43]3 years ago
3 0

Answer:

It will be converted into thermal energy

Explanation:

In an ideal world, energy can be converted from one  form into another without any loss of energy.

However, in the real world this does not really happen, because there are some frictional forces always acting on the system we are considering. Because of this, part of the mechanical energy of the system is always converted into thermal energy (as heat), and it cannot be "retrieved" back, so it becomes a form of energy that cannot be used anymore.

In this example, the initial mechanical energy of the system is the elastic potential energy of the spring, which is

U = 10 J

Later, when the spring is released, this energy is converted into kinetic energy of the moving car. However, as we are told, only part of this energy is actually converted, which is

K = 8 J

However, the law of conservation of energy states that energy cannot be created or destroyed, but only transformed: this means that the other 2 J of energy have not been actually destroyed, but they have only been converted into another form of energy, which is thermal energy, due to the presence of frictional forces.

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A string has its 4th harmonic at 31.5 Hz. What is the fundamental frequency?
seropon [69]

Given data

*The given 4th harmonic frequency is 31.5 Hz

The fundamental frequency is calculated as

\begin{gathered} f_n=\frac{31.5}{4} \\ =7.875\text{ Hz} \end{gathered}

Hence, the fundamental frequency is 7.875 Hz

5 0
1 year ago
At 7.0°c, the volume of a gas is 49 ml. at the same pressure, its volume is 74 ml at what temperature?
Rashid [163]
So i converted everything first; 
<span>7.0 C ---> 280 K </span>
<span>49 mL---> 0.049 L </span>
<span>74mL---> 0.074 L </span>
<span>THEN I tried setting it up by the combined law formula which is P1V1/T1=P2V2/T2 </span>
8 0
3 years ago
Determine the magnitude of the current flowing through a 4.7 kilo ohms resistor if the voltage across it is (a) 1mV (b) 10 V (c)
mariarad [96]

Answer:

213 nA

2.13 mA

851e^-t μA

Explanation:

We have a pretty straightforward question here.

Ohms Law states that the current in an electric circuit is directly proportional to the voltage and inversely proportional to the resistance in the circuit. It is mathematically written as

V = IR, since we need I, we can write that

I = V/R

a) at V = 1 mV

I = (1 * 10^-3) / 4.7 * 10^3

I = 2.13 * 10^-7 A or 213 nA

b) at V = 10 V

I = 10 / 4.7 * 10^3

I = 0.00213 A or 2.13 mA

c) at V = 4e^-t

I = 4e^-t / 4.7 * 10^3

I = 0.000851e^-t A or 851e^-t μA

5 0
2 years ago
A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.
ivann1987 [24]

Answer:

v₂ = 176.24 m/s

Explanation:

given,

angle of projectile = 45°

speed = v₁ = 150 m/s

for second trail

speed = v₂ = ?

angle of projectile = 37°

maximum height attained formula,

H_{max}= \dfrac{v^2 sin^2(\theta)}{g}

now,

H_{max}= \dfrac{v_1^2 sin^2(\theta_1)}{g}

H_{max}= \dfrac{v_2^2 sin^2(\theta_2)}{g}

now, equating both the equations

\dfrac{v_2^2}{v_1^2}=\dfrac{sin^2(\theta_1)}{sin^2(\theta_2)}

\dfrac{v_2^2}{150^2}=\dfrac{sin^2(45^0)}{sin^2(37^0)}

   v₂² = 31061.79

   v₂ = 176.24 m/s

velocity of projectile would be equal to v₂ = 176.24 m/s

8 0
3 years ago
How much potential energy does a 40-kg medicine ball gain when it is lifted 5 m? Use the formula: GPE= mass X gravity (9.8 m/s2)
Ronch [10]
The answer is c: <span>1960 J

</span>Potential Energy :
<span>PE = m x g x h = 40*9.8*5=1960
</span>
4 0
3 years ago
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