The human eye is able to see images and colors because of the specialized photoreceptor cells in the retina called rods and cones.
Answer:
547 L of water vapour
Explanation:
Equation of reaction: 2[CaSO4.2H20] + Heat ---> 2[CaSO4.½H2O] + 3H20
From the equation of reaction above, 2 moles of gypsum when heated produces 2 moles of plaster of Paris and 3 moles of water vapour.
Molar mass of gypsum = 172 g/mol
Molar mass of H2O = 18 g/mol
Therefore, 2 * 172 g of gypsum produces 3 * 18 g of water vapour
i.e. 344 g of gypsum produces 54 g of H2O
2 Kg(2000 g) of gypsum will produce (54 * 2000)/344 g of water vapour = 313.95 of water vapour.
Volume of water vapour produced = mass/density
Volume of water vapour = 313.95 g/ 0.574 g/L = 547 L of water vapour
Therefore 547 L of water vapour are produced
At STP conditions, 0.25 moles of CO2(g), H2(g), NH3(g)
The answers are:
<span>1. Will contain the same number of molecules </span>
3. Will occupy the same volume
0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.
<h3>What is an ideal gas equation?</h3>
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
V=5 L
P = 1.05 atm
T = 296 K
Putting value in the given equation:


Moles = 0.216 moles
Hence, 0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.
Learn more about the ideal gas here:
brainly.com/question/27691721
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