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kaheart [24]
3 years ago
13

Balance the equation Mg(s) + O2(g) -> MgO(s)​

Chemistry
1 answer:
Bess [88]3 years ago
5 0

Answer:

2Mg(s) + O2 (g) -> 2MgO(g)

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A student has a piece of aluminum metal. Which is the most reasonable assumption the student could make about the metal?
Rudik [331]

The metals are elements which have low ionization potential and can lose electrons easily

the other physical characteristics associated with them and hence with Aluminium are

a) they can conduct electricity in molten state, hence It would only conduct electricity if it were melted.

b) It could be stretched into a thin wire. It means it is ductile.

In case of given aluminium metal the correct answer is

it could be stretched to thin wire

3 0
3 years ago
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What is the electron configuration for N (nitrogen)?
ollegr [7]

Answer:

1s^22s^22p^3

Explanation:

Nitrogen has the atomic number = 7

So, No. of electrons = 7

<u><em>Electronic Configuration:</em></u>

1s^22s^22p^3

<u>Remember that:</u>

s sub shell holds upto 2 electrons while p sub shell upto 6

7 0
4 years ago
You need to produce a buffer solution that has a pH of 5.00. You already have a solution that contains 10. mmolmmol (millimoles)
weeeeeb [17]

Answer : The  millimoles of acetate need to add to this solution will be, 18.2 mmol

Explanation :

For acetic acid, pK_a=4.74

Moles of of acetic acid = 10 mmol

pH = 5.00

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

5.00=4.74+\log (\frac{Salt}{10})

Salt=18.2mmol

Thus, the millimoles of acetate need to add to this solution will be, 18.2 mmol

3 0
4 years ago
Calculate the mass percent of carbon in the following molecule: Mn3[Mn(CO)4]3
Lilit [14]

Answer:

21.63 %

Explanation:

The molar mass of Mn₃[Mn(CO)₄]₃ is 665.64 g/mol.

Let's assume we have 1 mol of Mn₃[Mn(CO)₄]₃, if that were the case then we would have 665.64 grams.

There are 12 C moles per Mn₃[Mn(CO)₄]₃, with that in mind we<u> calculate the weight of 12 C moles:</u>

  • 12 mol C * 12 g/mol = 144 g

Finally we <u>calculate the mass percent of carbon</u>:

  • 144 g / 665.64 g * 100% = 21.63 %
3 0
3 years ago
Mnemonic device for remembering the four layers of the atmosphere?
Iteru [2.4K]
TSMTE,

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Ellen
4 0
3 years ago
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