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kaheart [24]
3 years ago
13

Balance the equation Mg(s) + O2(g) -> MgO(s)​

Chemistry
1 answer:
Bess [88]3 years ago
5 0

Answer:

2Mg(s) + O2 (g) -> 2MgO(g)

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Substance A has the following properties.
ella [17]

It will take 1.11 min to heat the sample to its melting point.

Melting point = - 20°C

Boiling point = 85°C

∆H of fusion = 180 J/g

∆H of vap = 500 J/g

C(solid) = 1.0 J/g °C

C(liquid) = 2.5 J/g °C

C(gas) = 0.5 J/g °C

Mass of sample = 25 g

Initial temperature = - 40°C

Final temperature = 100°C

Rate of heating = 450 J/min

Specific heat capacity formula:- q = m ×C×∆T

Here, q = heat energy

        m = mass

        C = specific heat

      ∆T = temperature change

Melting point = - 20°C

C(solid) = 1.0 J/g °C

∆T = final temperature - initial temperature = -20 - (-40) = 20

Put these value in  Specific heat capacity formula

q = m ×C×∆T

q = 25×1.0×20

   =500J

The Rate of heating = 450 J/min

i.e. 450J = 1min

so, 500J = 1.11min

1.11 minutes does it take to heat the sample to its melting point.

The specific heat capacity is defined as the amount of heat absorbed in line with unit mass of the material whilst its temperature increases 1 °C.

Learn more about specific heat capacity here:- brainly.com/question/26866234

#SPJ4

3 0
1 year ago
What is the average mass of an electron? A. 1 amu B. 1,837 amu C. 1/1,837
diamong [38]

Answer:

C. 1/1,837

Explanation:

3 0
3 years ago
Free 100 for the boys​
Drupady [299]
Ok thanks wkwksnmenenenenenenwnwnnwnwnwnw
6 0
3 years ago
Read 2 more answers
Does the hydrogen molecule obey the octet rule?
Alja [10]

Explanation:

Hydrogen does not obey the octet rule. Boron does not always

obey the octet rule and in fact forms Lewis acids such as BF3 which

only has 6 electrons.

6 0
3 years ago
When the pressure that a gas exerts on a sealed container changes from 1100 bar to 75.5 bar, the temperature changes from k to 2
Serjik [45]
Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant
\frac{P1}{T1} =  \frac{P2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
\frac{1100 bar}{T}  =  \frac{75.5 bar}{298 K}
T = 4342 K
initial temperature was 4342 K
7 0
3 years ago
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