1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Georgia [21]
3 years ago
8

A 2.31 kg rope is stretched between supports 10.4 m apart. If one end of the rope is tweaked, how long will it take for the resu

lting disturbance to reach the other end? Assume that the tension in the rope is 55.7 N.
a. 0.615 s
b. 0.664 s
c. 0.720 s
d. 0.699 s
Physics
1 answer:
zlopas [31]3 years ago
4 0

Answer:

t = 0.657 s

Explanation:

First, let's use the appropiate equations to solve this:

V = √T/u

This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.

Where:

V: Speed of the disturbance

T: Tension of the rope

u: linear density of the rope.

The density of the rope can be calculated using the following expression:

u = M/L

Where:

M: mass of the rope

L: Length of the rope.

We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:

u = 2.31 / 10.4 = 0.222 kg/m

Now, replacing in the first equation:

V = √55.7/0.222 = √250.9

V = 15.84 m/s

Finally the time can be calculated with the following expression:

V = L/t ----> t = L/V

Replacing:

t = 10.4 / 15.84

t = 0.657 s

You might be interested in
The graph represents velocity over time.<br> What is the acceleration?
Semmy [17]

Answer:

I think the answer is 0.2 m/s2

Explanation:

7 0
2 years ago
A constant net force acts on an object. which of the following best describes the object's motion?
Anton [14]
The object<span> is moving with a decreasing acceleration. The </span>object<span> is moving with </span>a constant<span> velocity.</span>
4 0
3 years ago
The bar graph shows energy data taken from a roller coaster at a theme park. Analyze the data and assess its validity. In 3–5 se
alexdok [17]

The data given in the bar graph is valid because it follows the law of conservation of energy, since the GPE at top of 2nd hill plus KE at top of 2nd hill equals KE at bottom of 1st hill.

<h3>What is law of conservation of energy?</h3>

The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.

Based on the law of conservation of energy, kinetic energy of a roller coaster can be converted into potential energy of the roller coaster and vice versa.

ΔK.E = ΔP.E

where;

  • ΔK.E is change in kinetic energy
  • ΔP.E is change in potential energy

The kinetic energy of the coaster is greatest at the bottom of the hill, as the coaster moves upward, the kinetic energy decreases and will be converted into potential energy. The potential energy of the coaster increases as the coaster moves up the hill and will become maximum at the highest point of the hill.

From the given data;

GPE at top of 2nd hill + KE at top of 2nd hill = KE at bottom of 1st hill

Learn more about conservation of energy here: brainly.com/question/166559

#SPJ1

6 0
1 year ago
Which would fall with a greater acceleration in a vacuum-a leaf or a stone?
hichkok12 [17]

They would fall with the same acceleration

4 0
3 years ago
Read 2 more answers
Consider a river flowing toward a lake at an average speed of 3 m/s at a rate of 550 m3/s at a location 58 m above the lake surf
Vladimir [108]

Answer:

1. 0.574 kJ/kg

2. 315.7 MW

Explanation:

1. The mechanical energy per unit mass of the river is given by:

E_{m} = E_{k} + E_{p}

E_{m} = \frac{1}{2}v^{2} + gh

Where:

Ek is the kinetic energy

Ep is the potential energy

v is the speed of the river = 3 m/s

g is the gravity = 9.81 m/s²

h is the height = 58 m

E_{m} = \frac{1}{2}(3 m/s)^{2} + 9.81 m/s^{2}*58 m = 0.574 kJ/Kg

Hence, the total mechanical energy of the river is 0.574 kJ/kg.

2. The power generation potential on the river is:

P = m(t)E_{m} = \rho*V(t)*E_{m} = 1000 kg/m^{3}*550 m^{3}/s*0.574 kJ/kg = 315.7 MW

Therefore, the power generation potential of the entire river is 315.7 MW.

I hope it helps you!

4 0
3 years ago
Other questions:
  • Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150
    6·1 answer
  • A tiger leaps horizotally from a 15.5 m high rock with a speed of 7.5 m/s. How
    5·1 answer
  • Two motorcycles travel along a straight road heading due north. At t = 0 motorcycle 1 is at x = 50.0 m and moves with a constant
    13·1 answer
  • Jenna made an electric circuit as seen in the picture. She placed a thermometer near her light bulb. After the light bulb was tu
    9·2 answers
  • 18. A net force of 1.0N acts on a 4.0-kg object, initially at rest, for 4.0 seconds. What is the distance the object moves durin
    5·2 answers
  • Where is the us constitution does it mention anything about local governments
    8·1 answer
  • A ball is thrown vertically upward at 24.0 ms can reach a height of 28.8m ( neglecting air resistance).The speed,in m/s,when it
    7·1 answer
  • The 243000-lb space-shuttle orbiter touches down at about 236 mi/hr. The drag chute is deployed at 189 mi/hr, the wheel brakes a
    8·1 answer
  • ਨਿਰਭਰ ਕਰਦੀ<br>ਇਬਾਣੀ ਸਰੀਰਜ ਸਮੱਰਥਾ ਜਿਹੜਾ ਕਿੰ- ਉਨ ਬਾਦ ਤੇ​
    11·1 answer
  • How does using the straw demonstrate “point of application” of a force?
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!