The launch speed of a horizontally launched projectile is 13.28 m/s.
<h3>
Time of motion of the projectile</h3>
The time of motion is calculated as follows;
t = √(2h / g)
where;
- h is height of the cliff
- g is acceleration due to gravity
t = √(2 x 19.3 / 9.8)
t = 1.98 s
<h3>Launch speed of the projectile</h3>
X = Vxt
Vx = X/t
Vx = (26.3)/(1.98)
Vx = 13.28 m/s
Thus, the launch speed of a horizontally launched projectile is 13.28 m/s.
Learn more about horizontal speed here: brainly.com/question/24949996
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The model is based on hypothesis to get an initial idea for analyzing a complex problem. Hence, the validity of a model is limited and may not be valid universally. On the other hand, theories and laws are confirmed hypothesis which are universally valid. These are formulated after repeated testings. theories are more explanatory.
v₀ = initial velocity of the mobile = 10 m/s
v = final velocity of the mobile = 20 m/s
a = acceleration of the mobile = 5 m/s²
d = distance traveled during this operation = ?
Using the kinematics equation
v² = v²₀ + 2 a d
inserting the above values in the equation
20² = 10² + 2 (5) d
400 = 100 + 10 d
subtracting 100 both side
400 - 100 = 100 - 100 + 10 d
300 = 10 d
dividing both side by 10
300/10 = 10 d/10
d = 30 m
hence mobile travels 30 m.
Answer:
2406 miles
Explanation:
Let A be the starting position, B the junction position and C the final position after flying the 3.5 hrs. Also, let b be the distance from the starting point:

#Distance traveled in 1.5hrs is;

#Distance traveled in next two hrs:

#Now using the Cosine Rule:

Hence, the pilot is 2406 miles from her starting position.