Which of these processes take place at the same temperature?

The highest concentration of dissolved gases is found in what type of water mass?

Maurinko [17]

Elephants are really cool

7 0

3 years ago

A gas exerts a pressure of 0.62 atm. Convert this to kPa and mmHg. Be sure to show your work.

IRINA_888 [86]

Answer:

The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg

Explanation:

Data

P = 0.62 atm

P = ? kPa

P = ? mmHg

Process

1.- Look for the conversion factor of atm to kPa and mmHg

1 atm = 101.325 kPa

1 atm = 760 mmHg

2.- Do the conversions

1 atm ----------------- 101.325 kPa

0.62 atm ------------ x

x = (0,62 x 101.325) / 1

x = 62.82 kPa

1 atm ------------------ 760 mmHg

0.62 atm ------------ x

x = (0.62 x 760)/1

x = 471.2 mmHg

4 0

4 years ago

Formulate a hypothesis about the stoichiometry of the reaction between NaCl and AgNO3.

MAXImum [283]

Answer:

AgCl + NaNO3 would be the products of the reaction between sodium chloride and silver nitrate.

The stoichiometry of this reaction is written below, and it is because for this reaction to be fulfilled the products have to be in equilibrium with the reactants, since the mass in the reaction is conserved and must be balanced in the amount of molecules that they react to each other.

Explanation:

NaCl + AgNO3 -------------- AgCl + NaNO3

3 0

4 years ago

Pulses A, B, C, and D all travel at 10 m/s on the same string but in opposite directions. The string is depicted at time t=0 in

Anit [1.1K]

(a) The displacement of point P at time t=0.10s is determined as +2cm.

(b) The displacement of point P at time t=0.20s is determined as -2cm.

<h3>What is displacement?</h3>

Displacement is the change in position of an object. It is obtained from the product of velocity and time of motion.

x = vt

<h3>Displacement of the waves after 0.1 s</h3>

x = 10 m/s x 0.1 s = 1 m

Each wave will travel 1 m to the right or to the left, depending on the initial direction.

wave B from left will stop at point 0 m
wave A from left will stop at point -1 m
wave C from right will stop at point 0 m
wave D from right will stop at point + 1 m

wave B and C superimposed and the displacement will be between A and D.

Amplitude of A = - 2cm

Amplitude of D = + 4cm

Displacement of point P = 4 cm - 2 cm = 2cm

<h3>Displacement of the waves after 0.2 s</h3>

x = 10 m/s x 0.1 s = 2 m

Each wave will travel 2 m to the right or to the left, depending on the initial direction.

wave B from left will stop at point 1 m
wave A from left will stop at point 0 m
wave C from right will stop at point -1 m
wave D from right will stop at point 0 m

Displacement of point P = (amplitude B + amplitude C) + (amplitude A + amplitude D)

Displacement of point P= (2cm - 2cm) + (2 cm - 4cm)= -2cm

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

8 0

2 years ago

In a aqueous solution of 4-chlorobutanoic acid , what is the percentage of -chlorobutanoic acid that is dissociated

lord [1]

Answer:

Explanation:

Let assume that the missing aqueous solution of 4-chlorobutanoic acid = 0.76 M

Then, the dissociation of 4-chlorobutanoic acid can be expressed as:

$\mathsf{C_3H_6ClCO_2H }$ ⇄ $\mathsf{C_3H_6ClCO_2^-}$ + $\mathsf{H^+}$

The ICE table can be computed as:

$\mathsf{C_3H_6ClCO_2H }$ ⇄ $\mathsf{C_3H_6ClCO_2^-}$ + $\mathsf{H^+}$

Initial 0.76 - -

Change -x +x +x

Equilibrium 0.76 - x x x

$K_a = \dfrac{[\mathsf{C_3H_6ClCO_2^-}] [\mathsf{H^+}]}{\mathsf{[C_3H_6ClCO_2H ]}}$

$K_a = \dfrac{[x] [x]}{ [0.76-x]}$

where:

$K_a = 3.02*10^{-5}$

$3.02*10^{-5} = \dfrac{x^2}{ [0.76-x]}$

however, the value of x is so negligible:

0.76 -x = 0.76

Then:

$3.02*10^{-5}*0.76 = x^2$

$x=\sqrt{3.02*10^{-5}*0.76 }$

x = 0.00479 M

∴

$x = \mathsf{[C_3H_6ClCO_2^-] = [H^+]=}$ 0.00479 M

$\mathsf{C_3H_6ClCO_2H }$ = (0.76 - 0.00479) M

= 0.75521 M

Finally, the percentage of the acid dissociated is;

= ( 0.00479 / 0.76) × 100

= 0.630 M

7 0

3 years ago