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stira [4]
3 years ago
9

What volume of 1.25M HCl would be required to prepare 180 mL of a 0.500M HCl solution? A. 2.2 x 103 mL B. 450 mL C. 72 mL D. 0.0

14 mL
Chemistry
1 answer:
OverLord2011 [107]3 years ago
4 0

To solve this we use the dilution equation used in chemistry, 

M1 V1 = M2 V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

M1 V1 = M2 V2

1.25 M x V1 = 0.500 M x 180 mL

<span>V1 =72 mL of the concentrated solution</span>

<span>Therefore, the correct answer would be option C.</span>

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An oxybromate compound, kbrox, where x is unknown, is analyzed and found to contain 43.66 % br.
aniked [119]

Answer is: an oxybromate compound is KBrO₄ (x = 4).

ω(Br) = 43.66% ÷ 100%.

ω(Br) = 0.4366; mass percentage of bromine.

If we take 100 grams of compound:

m(Br) = ω(Br) · 100 g.

m(Br) = 0.4366 · 100 g.

m(Br) = 43.66 g; mass of bromine.

n(Br) = m(Br) ÷ M(Br).

n(Br) = 43.66 g ÷ 79.9 g/mol,

n(Br) = 0.55 mol; amoun of bromine.

From chemical formula (KBrOₓ), amount of potassium is equal to amount of bromine: n(Br) = n(K).

m(K) = 0.55 mol · 39.1 g/mol.

m(K) = 21.365 g; mass of potassium in the compound.

m(O) = 100 g - 21.365 g - 43.66 g.

m(O) =34.97 g; mass of oxygen.

n(O) = 34.97 g ÷ 16 g/mol.

n(O) = 2.185 mol.

n(K) : n(Br) : n(O) = 0.55 mol : 0.55 mol : 2.185 mol /÷ 0.55 mol.

n(K) : n(Br) : n(O) = 1 : 1 : 4.

6 0
3 years ago
1. A compound is found to contain
satela [25.4K]

Answer:

FeSO2

Explanation:

Please see attached picture for full solution.

8 0
2 years ago
an unknown molecule is found to consist of 24.2% carbon by mass, 4.0% hydrogen by mass and the remaining mass is due to chlorine
Paha777 [63]

Answer:

C3 H6 Cl 3

Explanation:

C -24.2%

H -  4.0%

Cl - (100-24.2 - 4.0)=73.8 %

We can take 100g of the substance, then we have

C -24.2 g

H -  4.0 g

Cl - 73.8 g

Find the moles of these elements

C -24.2 g/12.0 g/mol =2.0 mol

H -  4.0 g/1.0 g/mol = 4. 0 mol

Cl - 73.8 g/ 35.5 g/mol = 2.1 mol

Ratio of these elements gives simplest formula of the substance

C : H : Cl = 2 : 4 : 2 = 1 : 2 : 1

CH2Cl

Molar mass (CH2Cl) = 1*12.0 +2*1.0 + 1*35.5 = 49.5 g/mol

Real molar mass = 150  g/mol

real molar mass/ Molar mass (CH2Cl) = 150 /49.5=3

So, Real formula should be C3 H6 Cl 3.

4 0
3 years ago
Read 2 more answers
HURRY
Ugo [173]

Answer:

11.647g of water may be produced.

Explanation:

chemistry of the reaction:

2O2 + 2H2 ----> 2H2O + O2

64g + 4g yields 36g of water,

20g + 2g yields 11.647058824g of water

5 0
3 years ago
Suppose you were given a substance and asked to determine weather or not it was a plasma. Write the characteristics you would lo
Sphinxa [80]

Electrical conductivity, electromagnetism, and temperature are the features that one would look for in order to determine plasma. Plasma refers to a hot ionized gas possessing high electrical conductivity. It is electrically neutral with negative and positive particles. It can be considered the most abundant form of matter in the universe.  

The features of plasma are substantially distinct from those of the usual neutral gases so that plasmas are regarded as a different fourth state of matter.  


5 0
2 years ago
Read 2 more answers
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