Explanation:
Since, the atomic number of nitrogen is 7 and its electronic distribution is 2, 5. So, in order to attain stability it needs to gain 3 electrons.
Hence, when it chemically combines another nitrogen atom then as both the atoms are non-metals. So, sharing of electrons will take place.
Also, there is no difference in electronegativity of two nitrogen atoms. Hence, compound formed 
is non-polar covalent in nature.
Answer:
1. Lysine
2. Aspartic acid
3. Serine
4. Alanine
5. Tryptophan
Explanation:
Amino acids are biomolecules that contain two functional groups and one R side chain. The two functional groups are: carboxyl group and amino group.
The α-amino acids are the amino acids in which the two functional groups and the R side chain are attached to the α-carbon of the amino acid. They are total 22 α-amino acids.
1. A basic amino acid: Lysine is a positively charged, polar basic amino acid with a lysyl side chain.
2. An acidic amino acid: Aspartic acid is a negatively charged, polar acidic amino acid with an acidic carboxymethyl group.
3. A neutral polar amino acid: Serine is a polar and neutral amino acid with a hydroxymethyl group.
4. A non-polar aliphatic amino acid: Alanine is an aliphatic, nonpolar and neutral amino acid with a methyl side chain.
5. An aromatic amino acid: Tryptophan is an aromatic, nonpolar and neutral amino acid with an indole side chain.
Answer:
4. 60 neutrons.
Explanation:
The given isotopes;
¹⁰⁶₄₆Pd
In this isotope, we can deduce that the mass number is the superscript and the atomic number is the subscript;
Mass number = 106
Atomic number = 46
Mass number is the number of protons and neutrons in an atom;
Mass number = Protons + neutrons
Atomic number is the number of protons
So, Number of protons = 46
Number of neutrons = Mass number - Atomic number
= 106 - 46
= 60
Number of neutrons = 60
Answer:
Sodium has 1 valence electron and bismuth has 83 electrons (5 valence electrons)
Explanation:
Answer: Volume of 0.25 M solution is 38 ml
Explanation: Amount of substance n remains same.
n = c1V1 = c2V2 Solve V2 = V1c1 / c2 = 73,0 ml · 0.13 M / 0.25 M = 37.96 ml
