1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kenny6666 [7]
3 years ago
5

Describe what happens when two substances at different temperatures come into contact. Describe how the law of conservation of e

nergy applies to this system.
Chemistry
1 answer:
Mrac [35]3 years ago
3 0
When two substances at different tempeartures como into contact, the substance that is at higher temperature will transfer energy, in the form of heat, to the substance that is at lower temperature, until their temperatures get equal.

In this case, if the two substances are isolated of the rest of the universe, the law of conservation of energy states tha the heat released by the substance initially at higher temperature is the same amount of heat gained by the substance originally at lower temperature.

 
You might be interested in
A newborn eats 8 times a day. At each feeding, he eats 2.5 ounces of formula. How many days would it take to eat 100 ounces
fredd [130]

Answer:

It would take 5 days

Explanation:

1. 2.5 times 8 is 20 ounces

2. 2.5 times 16 is 40 ounces

3. 2.5 times 24 is 60 ounces

4. 2.5 times 32 is 80 ounces

5. 2.5 times 40 is 100 ounces

6 0
3 years ago
Read 2 more answers
How many lone pairs of electrons in lewis structure of CH3 OH
Brums [2.3K]
There would be 2 which would be on the oxygen
4 0
3 years ago
Which equation has x = 5 as the solution?
Natali5045456 [20]

Answer:

x-10 should be the answer

8 0
3 years ago
Giveaway!! 2 more coming up.<br><br> hope you get it ! &lt;3
abruzzese [7]

Answer:

k

Explanation:

7 0
2 years ago
Read 2 more answers
Instead of using ratios for back titrations we can also use molarities, if our solutions are standardized. A 0.196 g sample of a
kvv77 [185]

Answer:

The mass percent of Al(OH)₃ is 15.3%

Explanation:

The reaction is:

Al(OH)₃ + 3HCl = AlCl₃ + 3H₂O

The excess acid is neutralized with a solution of sodium hidroxide, in the reaction:

NaOH + HCl = NaCl + H₂O

The total moles of HCl is:

n_{HCl,total} =M_{HCl} *V_{HCl} =0.111*0.025=2.78x10^{-3} moles

From the second titration, the moles of excess of HCl is:

n_{HCl,excess} =n_{NaOH} =M_{NaOH} *V_{NaOH} =0.132*0.01105=1.46x10^{-3} moles

The difference between the total and excess of HCl, it can be know the moles that reacts with the aluminum hydroxide, is:

n_{HCl,reacts} =n_{HCl,total}-n_{HCl,excess} =2.78x10^{-3} moles-1.46x10^{-3} moles=1.32x10^{-3} moles

The ratio between HCl and Al(OH)₃ is 3:1. The MW for aluminum hydroxide is 78 g/mol, thus:

m_{Al(OH)3} =1.32x10^{-3} molesHCl*\frac{1molAl(OH)3}{3molesHCl} *\frac{78gAl(OH)3}{1molAl(OH)3} =0.03g

The percentage of Al(OH)₃ is:

Percentage-Al(OH)3=\frac{m_{Al(OH)3} }{m_{antiacid} } *100=\frac{0.03}{0.196} =15.3%

3 0
3 years ago
Other questions:
  • can someone help me create my own chemistry meme with this picture.. ( don’t copy and paste from internet please ) THANKS !
    11·2 answers
  • Select the correct answer. Which is the most electronegative element? A. nitrogen B. fluorine C. sodium D. cesium E. hydrogen
    9·2 answers
  • 125mm hg into atmosphere
    14·1 answer
  • The piece of solid metal can be described as ​
    10·1 answer
  • In a 51.0-g aqueous solution of methanol ch4o the mole fraction of methanol is 0.270. what is the mass of each component?
    9·1 answer
  • Your mother has an unlabeled bottle of clear liquid in the refrigerator. You pour a small cup of the liquid and taste it, and it
    11·1 answer
  • What is the mass of 1.25 mol of zinc ​
    13·1 answer
  • Compare the patterns of earthquakes, volcanoes, and mountain ranges on earth?
    8·1 answer
  • Which material is an insulator against electric current?
    10·2 answers
  • Grams in 1.083e+24<br> Molecules Na BR<br><br><br> Please help explain why
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!