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GalinKa [24]
3 years ago
15

7. How many seconds would it take a car travelling at 100.0 km/h to travel a distance of 16 m?

Physics
2 answers:
alexira [117]3 years ago
8 0

Answer: 0.58 s

Explanation: Solution attached:

Convert first 100.0 km/h to m/s

100.0 km/h x ( 1000 m / 1 km ) x ( 1h / 3600s ) + 27.8 m/s

Use v= d / t and derive too find t:

t = d / v

 = 16 m / 27.8 m/s

 = 0.58 s

cancel out meters and the remaining unit is in seconds.

tatiyna3 years ago
5 0

Answer: Time, t = 0.57 seconds

Explanation:

Speed of the car, v = 100 km/h = 27.77 m/s

Distance covered by the car, d = 16 m

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Answer:

mu = 0.56

Explanation:

The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

v^2=v_0^2+2ax\\

v: final speed = 0m/s (the car stops)

v_o: initial speed in the interval of interest = 60km/h

    = 60(1000m)/(3600s) = 16.66m/s

x: distance = 25m

BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}

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F_f=ma=(1490kg)(5.55m/s^2)=8271.15N

Furthermore, you use the relation between the friction force and the friction coefficient:

F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56

hence, the friction coefficient is 0.56

6 0
3 years ago
A horizontal 2.00\ m2.00 m long, 5.00\ kg5.00 kg uniform beam that lies along the east-west direction is acted on by two forces.
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Answer: 240\ rad/s^2

Explanation:

Given

Length of beam l=2\ m

mass of beam m=5\ kg

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Torque is the product of moment of inertia and angular acceleration

\Rightarrow \tau=I\alpha\\\\\Rightarrow 400=\dfrac{5}{3}\times \alpha\\\\\Rightarrow \alpha =240\ rad/s^2

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