Answer:
the velocity of the bullet-wood system after the collision is 2.48 m/s
Explanation:
Given;
mass of the bullet, m₀ = 20 g = 0.02 kg
velocity of the bullet, v₀ = 250 m/s
mass of the wood, m₁ = 2 kg
velocity of the wood, v₁ = 0
Let the velocity of the bullet-wood system after collision = v
Apply the principle of conservation of linear momentum to calculate the final velocity of the system;
Initial momentum = final momentum
m₀v₀ + m₁v₁ = v(m₀ + m₁)
0.02 x 250 + 2 x 0 = v(2 + 0.02)
5 + 0 = v(2.02)
5 = 2.02v
v = 5/2.02
v = 2.48 m/s
Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s
The ball may attracted to the magnet.
<h3>How can we understand that the hanging ball will be attracted to the magnet or not?</h3>
- From the question, we understand that the ball is attracted by the north pole of the bar magnet, then the bar magnet flipped over and the south pole is brought near the hanging ball.
- As we know, in this type of experiments of bar magnet most of the times the ball is made out of steel.
- Steel is a magnetic material.
- Magnetic materials gets attracted to the magnet at both the North and South pole.
- This can be compared to how neutral objects also gets attracted to the positively and negatively charged rods through the Polarization force.
So, If the bar magnet is flipped over and the south pole is brought near the hanging ball, The ball will be attracted to the magnet.
Learn more about the bar magnet:
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Answer:
500; 300 feet.
Explanation:
A turn signal lamp can be defined as an amber blinking lamp which indicates a driver's intent to change direction. It is extremely important that drivers gives a turn signal (flashing light) on the side toward which he or she is turning either left or right.
Simply stated, the turn signal lamp indicate the driver's intent to turn either leftward or rightward by displaying flashing lights to the front and rear of his or her vehicle.
A turn signal lamp must be visible in normal sunlight at a distance of at least 500 feet from the front and rear of the vehicle if the vehicle is at least 80 inches wide, and at least 300 feet from front and rear of the vehicle if the vehicle is less than 80 inches wide according to the transportation traffics code.
Answer:
5.49×10⁻⁴ lbm
Explanation:
Convert volume to m³.
V = (200 cm³) (1 m / 100 cm)³ = 0.0002 m³
Find mass in kg.
m = ρV
m = (1.24507 kg/m³) (0.0002 m³)
m = 0.000249 kg
Convert mass to lbm.
m = (0.000249 kg) (2.205 lbm/kg)
m = 0.000549 lbm
m = 5.49×10⁻⁴ lbm