40 N. If you’re using F=MA MxA would be 10x4 which would get you 40 N
The expression for the magnitude of the electric field between two uniform conducting plates is

Here, V is potential difference between plates and d is separation between plates.
As the potential 6.00 cm from the zero volt plate (and 4.00 cm from the other) is 420 V.
Therefore,

Thus, the electric field strength between the plates is 7000 V/ m
Answer:
A fast feather
Explanation:
The faster any item is, the more momentum it has
Average velocity = (x( 2.08 ) - x ( 0 )) / ( 2.08 s - 0 s )
x ( 2.08 ) = 1.42 * 2.08² - 0.05 * 2.08³ =
= 1.42 * 4.3264 - 0.443456 = 6.143484 - 0.443456 ≈ 5.7 m
v = ( 5.7 m - 0 m) / (2.08 s - 0 s ) = 5.7 / 2.08 m/s = 27.4 m/s