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choli [55]
3 years ago
10

What is the iupac name for this compound ch3-c(ch3) 2-ch2-chcl-ch3? ​

Chemistry
1 answer:
myrzilka [38]3 years ago
4 0

The IUPAC name of the above mentioned compound is "2-Chloro-4,4-dimethylpentane"

<u>Exaplanation:</u>

  • Since the above organic compound is an compound with only one saturated bond, It can be considered as a single bond compound, and hence we can conclude that as alkane.
  • It also has 5 carbon atoms, so it is termed as pentane.
  • From right to left we have to number the atoms, and 2 nd carbon atom contain Cl atom so it is termed as 2-Chloro and in the 4th position carbon atom contains 2 methyl groups, so it is termed as, 2-Chloro-4,4-dimethylpentane.
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A flashbulb of volume 2.70 mL contains O2(g) at a pressure of 2.30 atm and a temperature of 30.0 °C. How many grams of O2(g) doe
Sholpan [36]
P = 2.30 atm

Volume in liter = 2.70 mL / 1000 => 0.0027 L

Temperature in K = 30.0 + 273 => 303 K

R = 0.082 atm

molar mass O2 = 31.9988 g/mol

number of moles O2 :

P * V = n * R* T

2.30 * 0.0027 = n * 0.082 * 303

0.00621 = n * 24.846

n = 0.00621 / 24.846

n = 0.0002499 moles of O2

Mass of O2:

n = m / mm

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What is the mass of 2.90 ×1022 molecules of NaOH (Molar mass = 40.0 g/mol)?
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hope this helps!

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3 years ago
Which material has a crystalline structure at room temperature ( 20 degrees Celsius )
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8 0
3 years ago
Read 2 more answers
Question 1 (2 points)
bogdanovich [222]

Answer:

3.75 L

Explanation:

We can solve this problem by using <em>Charles' law</em>, which states:

  • V₁T₂=V₂T₁

Where subscript 1 stands for initial volume and temperature and subscript 2 for final volume and temperature, meaning that in this case:

  • V₁ = 2.5 L
  • T₂ = 300 K
  • V₂ = ?
  • T₁ = 200 K

We <u>input the data</u>:

  • 2.5 L * 300 K = V₂ * 200 K

And <u>solve for V₂</u>:

  • V₂ =  3.75 L
5 0
3 years ago
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