<h3>
Answer:</h3>
13 g CO₂
<h3>
General Formulas and Concepts:</h3>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] 6.7 L O₂
[Solve] g O₂
<u>Step 2: Identify Conversions</u>
[STP] 22.4 L = 1 mol
[PT] Molar Mass of O: 16.00 g/mol
[PT] Molar Mass of C: 12.01 g/mol
Molar Mass of CO₂: 12.01 + 2(16.00) = 44.01 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Divide/Multiply [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
13.1637 g CO₂ ≈ 13 g CO₂
Im sorry i can only do the last one the answer might be a, d, e. Im so sorry if im wrong
Atomic Number of Zinc is 30, means it contains 30 electrons. So, its electronic configuration is as follow,
1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰
As,
1s², 2s², 2p⁶, 3s², 3p⁶ = Argon
So,
Electronic configuration of Zinc in shorthand notation is as follow,
[Ar] 4s², 3d¹⁰
ang is a Malay and Indonesian word for "person".
<span>An Orang Mawas, a southeast Asian primate cryptid, about 2.5 meters tallAn Orang Pendek, a southeast Asian primate cryptid, about 1 meter tall<span>An orangutan</span></span><span>
</span>
Explanation:
Let relative ratio of one isotope (62.94 u) be X
Then, relative ratio of other isotope (64.93) will be (1 - X)
Now,
(62.94)x + (64.93)(1 - x) = 63.55
1.99x = 1.38
X = 0.69
<u>Relative Abundance</u> :
(62.94 u) isotope = 69 %
(64.93 u) isotope = 31 %