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photoshop1234 [79]
3 years ago
11

Lorenzo is making a prediction. “I learned that nonmetals increase in reactivity when moving from left to right. So I predict th

at xenon will be more reactive than iodine.” Is Lorenzo correct? If so, why? If not, explain his error.
Chemistry
2 answers:
slega [8]3 years ago
6 0
He’s incorrect because Xenon is a Noble Gas, making it one of the most unrest i’ve elements on the periodic table. Iodine as a Halogen is one of the most reactive.
blondinia [14]3 years ago
3 0

No, he isn't, because Xenon is a Noble Gas, meaning it doesn't react with anything else, as it already has a full outer shell

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vladimir1956 [14]

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The six commonly recognised metalloids are boron, silicon, germanium, arsenic, antimony, and tellurium. Five elements are less frequently so classified: carbon, aluminium, selenium, polonium, and astatine.

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3 years ago
The first step in industrial nitric acid production is the catalyzed oxidation of ammonia. Without a catalyst, a different react
murzikaleks [220]

<u>Answer:</u> The value of K_{eq} is 4.84\times 10^{-5}

<u>Explanation:</u>

We are given:

Initial moles of ammonia = 0.0280 moles

Initial moles of oxygen gas = 0.0120 moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}

So, concentration of ammonia = \frac{0.0280}{1.00}=0.0280M

Concentration of oxygen gas = \frac{0.0120}{1.00}=0.0120M

The given chemical equation follows:

                  4NH_3(g)+3O_2(g)\rightleftharpoons 2N_2(g)+6H_2O(g)

<u>Initial:</u>        0.0280        0.0120

<u>At eqllm:</u>    0.0280-4x   0.0120-3x   2x       6x

We are given:

Equilibrium concentration of nitrogen gas = 3.00\times 10^{-3}M=0.003

Evaluating the value of 'x', we get:

\Rightarrow 2x=0.003\\\\\Rightarrow x=0.0015M

Now, equilibrium concentration of ammonia = 0.0280-4x=[0.0280-(4\times 0.0015)]=0.022M

Equilibrium concentration of oxygen gas = 0.0120-3x=[0.0120-(3\times 0.0015)]=0.0075M

Equilibrium concentration of water = 6x=(6\times 0.0015)]=0.009M

The expression of K_{eq} for the above reaction follows:

K_{eq}=\frac{[H_2O]^6\times [N_2]^2}{[NH_3]^4\times [O_2]^3}

Putting values in above expression, we get:

K_{eq}=\frac{(0.009)^6\times (0.003)^2}{(0.022)^4\times (0.0075)^3}\\\\K_{eq}=4.84\times 10^{-5}

Hence, the value of K_{eq} is 4.84\times 10^{-5}

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6 0
2 years ago
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Explanation:

The given data is as follows.

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According to Fourier's law,

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Hence, putting the given values into the above formula as follows.

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Therefore, we can conclude that the rate of heat transfer is 5902.298 W.

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The most appropriate answer is C !! Cs is most electropositive and thus least electronegative !!
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