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mihalych1998 [28]
3 years ago
11

Explain why a fire engine’s siren sounds lower in pitch after the fire engine passes you.  

Physics
2 answers:
Gnoma [55]3 years ago
5 0
When a sound source is moving toward you, you hear a higher frequency than the source is putting out, and when the source is moving away from you, you hear a lower frequency than the real one. The whole process is called the Doppler effect. It works with light too.
Sedbober [7]3 years ago
3 0

Explanation:

Doppler effect: It is the phenomenon which occurs when there is relative motion between listener and source.

In this phenomenon, there is an apparent change in the frequency. There is an increase or decrease in frequency.

The frequency gets lower when the source and the listener are moving away from each other.

The frequency gets higher when the source and the listener are moving towards each other.

The pitch depends on the frequency. When the frequency increases then the pitch of the sound gets louder. When the frequency decreases then the pitch of the sound gets lower.

In the given problem, a fire engine's siren sounds lowers in pitch after the fire engine passes. Here, the source and the listener are moving away from each other. The frequency gets lower. Then, the pitch of the sound will also get lower.

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The principle of work states that the ratio of work output to work input is always
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Answer:

work output is always less than work input - the ratio is less than 1.

Explanation:

This principle comes from the fact that a machine or system cannot produce more work than is supplied to it, because this would violate the energy conservation law (work is a type of mechanical energy).

In theoretical machines called "ideal machines" the input work is the same as the output work, but these machines are only theoretical because in real applications there is always some type of energy loss, either in heat produced by a machine or processes for its operation, for this reason the output work is always less than the input work.

Regarding the ratio work output to work input:

\frac{WO}{WI} < 1

because work input WI is always greater than work output WO.

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Explanation:

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Answer:

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Inga [223]

Answer is c, they are equal:

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