Answer:
The actual angle is 30°
Explanation:
<h2>Equation of projectile:</h2><h2>y axis:</h2>
the velocity is Zero when the projectile reach in the maximum altitude:
When the time is vo/g the projectile are in the middle of the range.
<h2>x axis:</h2>
R=Range
**sin(2A)=2sin(A)cos(A)
<h2>The maximum range occurs when A=45°
(because sin(90°)=1)</h2><h2>The actual range R'=(2/√3)R:</h2>
Let B the actual angle of projectile
2B=60°
B=30°
Answer:
Please find the answer in the explanation
Explanation:
Given that some plants were watered with 4 different types of water (salt water, regular water, sugar water and distilled water). After a two-week period, the height of the plants is measured.
1.) The Independent Variable (IV) are the different types of water
2)Dependent Variable (DV) are the height of the plant. Dependent variable depends on the independent variable.
3)Constant is the unchanged parameter which is the period - the two weeks
4)Control: is the quantity of water used.
Answer:
Explanation:
<u>Dynamics of System of Masses</u>
We are given the characteristics of a system where two masses are connected by a massless string. The acceleration under these conditions is common to both objects. By analyzing the acting forces on each mass, we can find both the common acceleration and tension of the string.
Let's analyze the forces acting upon mass m1: To the right, we have the tension of the string that tries to move it in that direction. Opposite to the intent to move is the friction force to the left. Applying the Newton's second law, we have
Where
Thus
Now for the mass m2, in the vertical direction
Note that the sign of the acceleration is downwards since the mass m1 tends to move to the right and both masses are tied. W2 is the weight of the mass 2, thus
Replacing the value of T obtained above
Solving for a
Plugging in the given values:
Computing the tension of the string
Answer:
24 m to the right/ to the east