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tatuchka [14]
3 years ago
15

Which of the following is true about density and states of matter for most substances?

Physics
1 answer:
anyanavicka [17]3 years ago
4 0

<u><em>The right answer is "A) Substance is denser as a solid than as a gas" Trust me I just got it wrong because of this guy down here or girls not trying to judge</em></u>

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How much mass does the sun have? &lt;33
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Explanation:

1.989 × 10^30 kg

1.989 × 10^30 kg

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Why do atoms do group 1 element lose electrons to form cations
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Explanation:

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What would the coefficient of friction be if the frictional force was equal to the normal force? (Answer will be an number)
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If the car has the same initial velocity, and if the driver slams on the brakes at the same distance from the tree, then what wo
Elena L [17]

Answer: The question is incomplete or some details are missing. Here is the complete question ; (a) The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of −5.55 m/s2 for 4.05 s, making straight skid marks 63.0 m long, all the way to the tree. With what speed (in m/s) does the car then strike the tree? m/s

(b) What If? If the car has the same initial velocity, and if the driver slams on the brakes at the same distance from the tree, then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2

a ) With what speed (in m/s) does the car then strike the tree? m/s = 4.3125m/s

b) then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2 = -5.696m/s2

Explanation:

The detailed steps and calculation is as shown in the attached file.

6 0
3 years ago
If you are driving 90 km/hkm/h along a straight road and you look to the side for 2.2 ss , how far do you travel during this ina
ICE Princess25 [194]

Answer: 55m

Explanation:

Given the following :

Driving speed = 90km/hr

Inattentive period (time) = 2.2s

Distance during inattentive period =

(driving speed * time)

Converting driving speed from km/hr to m/s

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Therefore,

90km/hr = (90 * 1000) / 3600

90km/hr = (90000)/ 3600 = 25m/s

Therefore ;

Distance during inattentive period =

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Distance during inattentive period = (25m/s × 2.2s) = 55m

Distance traveled during inattentive period is 55m

6 0
3 years ago
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