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NARA [144]
3 years ago
12

Describe the general chemical formula of carbohydrates holt

Chemistry
1 answer:
REY [17]3 years ago
7 0
Monosaccharides are the simplest unit of carbohydrates. They're composed of carbon, hydrogen, and oxygen atoms, and they cannot be broken down further since they are already in their simplest form. Their general formula is (CH2O)n, where n is any number equal or greater than 3.
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If you have a 4.0 g of radioactive substance left after 4 half-lives have passed then how much did you have originally?
kirza4 [7]

4.0 +4.0= 8.0

8.0+8.0=16.0

16.0+16.0=32.0

32.0+32.0=64.0

6 0
3 years ago
Use the following periodic table to help you. Which of the following would be classified as a metalloid?
Rama09 [41]
Silicon is a metalloid
4 0
3 years ago
What is the mass percent of nitrogen in:<br><br> 1. N2O<br> 2. NO<br> 3. NO2<br> 4. N2O2
Temka [501]
We’re going to use the mass percent formula shown below:



For the percent by mass N, we’re going to rewrite the equation as:

98% (271 ratings)
View Complete Written Solution
Problem Details
Calculate the mass percent composition of nitrogen in each nitrogen-containing compound:

c. NO2
5 0
2 years ago
How many particles are in chemicals
stepan [7]

Answer:

6.022 x 10^23 particles

Explanation:

Chemists have chosen to count atoms and molecules using a unit called the mole (mol), from the Latin moles, meaning “pile” or “heap.”

One mole is 6.022 x 10^23 of the microscopic particles which make up the substance in question.

Hope this helped! :^)

4 0
2 years ago
1.Using the absorbance of the spinach extract and the equation of the trendline, determine the concentration of the extract solu
lys-0071 [83]

Answer:

Explanation:

From the given information:

We are to make use of the spinach absorbance extract which is the corrected absorbance  (y) = 0.306

And also the trendline equation:

y = 1609x + 0.0055

where,

x = absorbance of the spinach extract.

∴

0.306 = 1609x + 0.0055

collecting the like terms

0.306 - 0.0055 = 1609x

0.3005  = 1609x

x = 0.3005/1609

x = 1.8676 × 10⁻⁴

x ≅ 0.0002 M

No. of grams for the chlorophyll can be computed as follows:

recall that:

molar mass of chlorophyll = 893.5 g/mol

the volume = 25ml = (25/1000) L = 0.025 L

∴

In spinach solution, the no. of grams for the chlorophyll:

= (0.0002) mol/L × (893.5 g/mol) × (0.025) L

= 0.0044675 g

≅ 0.0045 g

In the spinach, the concentration of chlorophyll = no of grams of chlorophyll/ mass of the spinach

= 4.5 mg/0.1876 g

= 23.987 mg/g

≅ 24 mg/g

4 0
3 years ago
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