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Sunny_sXe [5.5K]
3 years ago
15

Beginning lonic compounds are made up of a__ and a__

Physics
2 answers:
nexus9112 [7]3 years ago
4 0

Answer:

metal and non-metal

Explanation :Ionic bonds are formed when a metal loses electrons and a non-metal gains said electrons.

Romashka-Z-Leto [24]3 years ago
3 0

Answer:

metal and non-metal

Explanation:

Ionic bonds are formed when a metal loses electrons and a non-metal gains said electrons.

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<em>a) increases</em>

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A uniform electric field exists in the region between two oppositely charged plane parallel plates. A proton is released from re
spayn [35]

The magnitude of the electric field can be calculated using the equation

E = \frac{F}{q}, where F is the Force acting on the proton and q is the charge of the proton.

We know that the charge of the proton is q = 1.6 x 10^{-19}  C

We have to calculate the Force first.

We know that F = ma from Newton's 2nd law, where m is the mass of the proton and a is the acceleration.

We know that the mass of the proton m = (1.67) X 10^{-27}  kg

So it turns out that we have to calculate acceleration before anything else.

In order to calculate the acceleration, we make use of the following data from the question:

Initial Velocity of the proton V_{i}  = 0

Distance traveled  D = 1.70 cm = 0.017 m

Time taken for the travel between the plates t = (1.48) X 10^{-6}  s

Acceleration a = ?

Using the equation, D = V_{i}t + \frac{1}{2} at^{2}, we get

Knowing that initial velocity is 0, the equation reduces to D = \frac{1}{2}at^{2}

Rearranging the equation so as to make a the subject of the formula, we have

a = \frac{2D}{t^{2} }

Plugging in the numbers and simplifying gives us a = 1.5 x 10^{10}   m/s^{2}

We can now calculate the Force using F = ma

Plugging in the known values, we get F = 2.5 x 10^{-17}  N

Using this, we can calculate E through the equation E = \frac{F}{q}

Plugging the numbers and simplifying gets us E = 156.25 N/C

Thus, the magnitude of the electric field between the plates of the capacitor is 156.25 N/C


B) To calculate the Final Velocity of the proton, we can make use of the equation

V_{f}  = V_{i}  + at

Plugging the numbers in and simplifying gets us V_{f}  = (2.22)  *  10^{4}  m/s

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