In a third class lever, the effort is located between the load and the fulcrum. If the fulcrum is closer to the load, then less effort is needed to move the load. If the fulcrum is closer to the effort, then the load will move a greater distance. ... These levers are useful for making precise movements.
Answer:

Now when it will reach at point B then its normal force is just equal to ZERO


Explanation:
Since we need to cross both the loops so least speed at the bottom must be

also by energy conservation this is gained by initial potential energy


so we will have

now we have

here we have
R = 7.5 m
so we have


Now when it will reach at point B then its normal force is just equal to ZERO

now when it reach point C then the speed will be
![mgh - mg(2R_c) = \frac{1}{2]mv_c^2](https://tex.z-dn.net/?f=mgh%20-%20mg%282R_c%29%20%3D%20%5Cfrac%7B1%7D%7B2%5Dmv_c%5E2)


now normal force at point C is given as



Answer:

Explanation:
A differential equation that contain a term with di(t)/dt is in a RL circuit. Here we have

where vr is the voltage in the resistance, vi is the voltage in the inductance and vb is the source voltage. But also we have that

where L is the inductance of the circuit, r is the resistance an i is the current. By replacing we have the differential equation

I hope this is useful for you
regards
Answer:
option A
Explanation:
given,
Kinetic energy of the car = 2000 J
speed of the car is doubled
we know,

........(1)
now, speed of the car is doubled
v' = 2 v


from equation (1)



Hence, the Kinetic energy would be equal to 8000 J.
The correct answer is option A.