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Juliette [100K]
3 years ago
5

What is the molar solubility of magnesium fluoride in a solution that is 0.40 m f− ions? The ksp of mgf2 is 6.4 × 10−9.

Chemistry
1 answer:
baherus [9]3 years ago
4 0

Answer:

S = 0.2 E-7 M

Explanation:

  • molar solubility (S) [=] mol/L
  • MgF2 ↔ Mg2+  +   2F-

          S              S         2S + 0.4

∴ [F-] = 0.4 m = 0.4 mol/Kg

∴ solvent: H2O ⇒ δH2O = (997 Kg/m³)*(m³/1000L) = 0.997 Kg/L

⇒ [F-] = (0.4 mol/Kg)*(0.997 Kg/L) = 0.3988 M ≅ 0.4 M

∴ Ksp = 6.4 E-9 = [S]*[2S + 0.4]²

⇒ 6.4 E-9 = (S)*(4S² + 1.6S + 0.16)

⇒ 6.4 E-9 = 4S³ + 1.6S² + 0.16S

⇒ 4S³ + 1.6S² + 0.16S - 6.4 E-9 = 0

⇒ S = 0.2 E-7 M

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