Alternating current (AC) flows half the time in one direction and half the time in the other, changing its polarity 120 times per second with 60-hertz current.
I think the question should be the below:
<span>What is the total distance, side to side, that the top of the building moves during such an oscillation?
</span>
Answer is the below:
<span>Acceleration .. a = (-) ω² x </span>
<span>(ω = equivalent ang. vel. = 2π.f) (x = displacement from equilibrium position) </span>
<span>x (max) = a(max) /ω² </span>
<span>x = (0.015 x 9.8m/s²) / (2π.f)² .. .. (0.147) / (2π*0.22)² .. .. ►x(max) = 0.077m .. (7.70cm)</span>
Answer: Physical changes only change the appearance of a substance, not its chemical composition. Chemical changes cause a substance to change into an entirely substance with a new chemical formula. Chemical changes are also known as chemical reactions.
Explanation:
40 seconds I’m pretty sure sorry if I’m wrong
Answer:
![E = (0.56 \times 10^8 ) r \ \ N/c](https://tex.z-dn.net/?f=E%20%20%20%3D%20%280.56%20%5Ctimes%2010%5E8%20%29%20r%20%20%20%5C%20%20%20%5C%20N%2Fc)
Explanation:
Given that:
![\rho_o = (10^{-3} ) \ c/m^3](https://tex.z-dn.net/?f=%5Crho_o%20%3D%20%2810%5E%7B-3%7D%20%29%20%5C%20c%2Fm%5E3)
R = (0.1) m
To find the electric field for r < R by using Gauss Law
![{\oint}E^{\to}* da^{\to} = \dfrac{Q_{enclosed}}{\varepsilon_o} --- (1)](https://tex.z-dn.net/?f=%7B%5Coint%7DE%5E%7B%5Cto%7D%2A%20da%5E%7B%5Cto%7D%20%3D%20%5Cdfrac%7BQ_%7Benclosed%7D%7D%7B%5Cvarepsilon_o%7D%20---%20%281%29)
For r < R
![Q_{enclosed}=(\rho) ( \pi r^2 ) l](https://tex.z-dn.net/?f=Q_%7Benclosed%7D%3D%28%5Crho%29%20%28%20%5Cpi%20r%5E2%20%29%20l)
![E*(2 \pi rl)= \dfrac{\rho ( \pi r ^2 l)}{\varepsilon_o}](https://tex.z-dn.net/?f=E%2A%282%20%5Cpi%20rl%29%3D%20%5Cdfrac%7B%5Crho%20%28%20%5Cpi%20r%20%5E2%20l%29%7D%7B%5Cvarepsilon_o%7D)
![E= \dfrac{\rho ( r)}{2 \varepsilon_o}](https://tex.z-dn.net/?f=E%3D%20%5Cdfrac%7B%5Crho%20%28%20r%29%7D%7B2%20%5Cvarepsilon_o%7D)
where;
![\varepsilon_o = 8.85 \times 10^{-12}](https://tex.z-dn.net/?f=%5Cvarepsilon_o%20%3D%208.85%20%5Ctimes%2010%5E%7B-12%7D)
![E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}](https://tex.z-dn.net/?f=E%3D%20%5Cdfrac%7B10%5E%7B-3%7D%20%28%20r%29%7D%7B2%20%288.85%20%5Ctimes%2010%5E%7B-12%7D%29%7D)
![E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}](https://tex.z-dn.net/?f=E%3D%20%5Cdfrac%7B10%5E%7B-3%7D%20%28%20r%29%7D%7B2%20%288.85%20%5Ctimes%2010%5E%7B-12%7D%29%7D)
![E = (0.56 \times 10^8 ) r \ \ N/c](https://tex.z-dn.net/?f=E%20%20%20%3D%20%280.56%20%5Ctimes%2010%5E8%20%29%20r%20%20%20%5C%20%20%20%5C%20N%2Fc)