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Masteriza [31]
3 years ago
10

The thickness of 25 pages of a physics textbook is 2 mm. How would you find the thickness, in mm, of 1 page?

Physics
1 answer:
melomori [17]3 years ago
6 0
To solve this question, all you have to do is set up a proportion with the information known and the information unknown and solve for the final variable, after setting them equal to each other.

2 mm/25 = ?/1

2/25 = 8/100 = 0.08 mm

1 page of the textbook would be 8 hundredths of a mm.
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Answer:

<h2>4.1 N</h2>

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From the question we have

force = 0.205 × 20

We have the final answer as

<h3>4.1 N</h3>

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Read 2 more answers
A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.
Advocard [28]

The potential across the capacitor at t = 1.0 seconds, 5.0 seconds, 20.0 seconds respectively is mathematically given as

  • t=0.476v
  • t=1.967v
  • V2=4.323v

<h3>What is the potential across the capacitor?</h3>

Question Parameters:

A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.

at

  • t = 1.0 seconds
  • 5.0 seconds
  • 20.0 seconds.

Generally, the equation for the Voltage is mathematically given as

v(t)=Vmax=(i-e^{-t/t})

Therefore

For t=1

V=5(i-e^{-1/10})

t=0.476v

For t=5s

V2=5(i-e^{-5/10})

t=1.967

For t=20s

V2=5(i-e^{-20/10})

V2=4.323v

Therefore, the values of voltages at the various times are

  • t=0.476v
  • t=1.967v
  • V2=4.323v

Read more about  Voltage

brainly.com/question/14883923

Complete Question

A 1.0 μF capacitor is being charged by a 5.0 V battery through a 10 MΩ resistor.

Determine the potential across the capacitor when t = 1.0 seconds, 5.0 seconds, 20.0 seconds.

7 0
2 years ago
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