Answer:
6. 7870 kg/m³ (3 s.f.)
7. 33.4 g (3 s.f.)
8. 12600 kg/m³ (3 s.f.)
Explanation:
6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.
1 kg= 1000g
1m³= 1 ×10⁶ cm³
Mass of iron bar
= 64.2g
= 64.2 ÷1000 kg
= 0.0642 kg
Volume of iron bar
= 8.16 cm³
= 8.16 ÷ 10⁶
![= 8.16 \times 10^{ - 6} \: kg](https://tex.z-dn.net/?f=%20%3D%208.16%20%5Ctimes%2010%5E%7B%20-%206%7D%20%5C%3A%20%20kg)
![\boxed{density = \frac{mass}{volume} }](https://tex.z-dn.net/?f=%5Cboxed%7Bdensity%20%3D%20%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20%7D)
Density of iron bar
![= \frac{0.0642}{8.16 \times 10^{ - 6} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B0.0642%7D%7B8.16%20%5Ctimes%2010%5E%7B%20-%206%7D%20%7D%20)
= 7870 kg/m³ (3 s.f.)
7.
![\boxed{mass = density \: \times volume}](https://tex.z-dn.net/?f=%5Cboxed%7Bmass%20%3D%20density%20%5C%3A%20%20%5Ctimes%20volume%7D)
Mass
= 1.16 ×28.8
= 33.408 g
= 33.4 g (3 s.f.)
8. Volume of brick
= 12 cm³
![= 12 \times 10^{ - 6} \: m^{3} \\ = 1.2 \times 10^{ - 5} \: m ^{3}](https://tex.z-dn.net/?f=%20%3D%2012%20%20%5Ctimes%20%2010%5E%7B%20-%206%7D%20%20%5C%3A%20m%5E%7B3%7D%20%20%5C%5C%20%20%3D%201.2%20%5Ctimes%2010%5E%7B%20-%205%7D%20%20%5C%3A%20m%20%5E%7B3%7D%20)
Mass of brick
= 151 g
= 151 ÷ 1000 kg
= 0.151 kg
Density of brick
= mass ÷ volume
![= \frac{0.151} {1.25 \times 10^{ - 5} } \\ = 12600 \: kg/ {m}^{3}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B0.151%7D%20%7B1.25%20%5Ctimes%2010%5E%7B%20-%205%7D%20%7D%20%20%5C%5C%20%20%3D%2012600%20%5C%3A%20kg%2F%20%7Bm%7D%5E%7B3%7D%20)
(3 s.f.)
Answer:
1.2×10²³ atoms.
Explanation:
Data obtained from the question include:
Mole of propanone = 0.20 mole
Number of atoms of propanone =.?
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ atoms.
This implies that 1 mole of propanone also contains 6.022×10²³ atoms.
Thus, we can obtain the number of atoms in 0.20 mole of propanone as illustrated below:
1 mole of propanone contains 6.022×10²³ atoms.
Therefore, 0.20 mole of propanone will contain = 0.2 × 6.022×10²³ = 1.2×10²³ atoms.
Thus, 0.20 mole of propanone contain
1.2×10²³ atoms.
What do I possibly answer here?
ask a full question pls!
The answer is 10-12. The relationship of pH and [H+] is pH = -lg[H+]. And the higher pH, the stronger base is. So the strongest base has the lowest concentration of H+.