Answer:
0.444atm
Explanation:
Using the combined gas law equation;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (
P2 = final pressure (
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to this question,
P1 = 101.3 kPa = 101.3 × 0.00987 = 0.999atm
P2 = ?
V1 = 80L
V2 = 160L (double of V1)
T1 = 34°C = 34 + 273 = 307K
T2 = 0°C = 0 + 273 = 273K
Using P1V1/T1 = P2V2/T2
0.999 × 80/307 = P2 × 160/273
79.92/307 = 160P2/273
Cross multiply
307 × 160P2 = 79.92 × 273
49120P2 = 21818.16
P2 = 21818.16 ÷ 49120
P2 = 0.444
P2 = 0.444atm
The gazelle has zero average acceleration because it's moving at a constant speed. Constant speed means no change in speed means zero acceleration.
The cheetah, on the other hand, changes its speed from 0 m/min to 1820 m/min in a matter of 3 seconds, so its average acceleration is
a[ave] = (1820 m/min - 0 m/min) / (3 s)
… = (1820 m/min) / (3/60 min)
… = 36,400 m/min²
… = (36,400 m) / (60 s)²
… = 91/9 m/s² ≈ 10.1 m/s²
<h2>Answer:</h2>
<u>Blue main Sequence stars have the greater initial mass</u>
<h2>Explanation:</h2>
Blue main sequence stars are the stars with surface temperatures of 20,000 to 50,000 Kelvin and can be 25 times larger than the Sun. They are extremely hot so they have blue color. The best example of this type of stars is Rigel which is the brightest star in the constellation of Orion.