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Fofino [41]
4 years ago
8

True or false.sliding friction is stronger than static friction

Physics
1 answer:
satela [25.4K]4 years ago
5 0

Static friction is stronger than sliding friction. So your question would be FALSE

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A 66.0−kg short-track ice skater is racing at a speed of 10.0 m/s when he falls down and slides across the ice into a padded wal
dexar [7]

Answer:

3300J

Explanation:

Work done is the energy that is lost by the skater

Formula for workdone = 1/2*mV^2

m = 66kg

V = 10m/s

Work done = 1/2 * 66 * 10^2

= 3300J

7 0
3 years ago
Establish the dimension of density​
mario62 [17]
Dimensional Formula of Density
The dimensional formula of density is given by,

[M1 L-3 T0]
Where,

M = Mass
L = Length
T = Time
Derivation

Density (ρ) = Mass × Volume-1 . . . . . (1)

The dimensional formula of volume = [M0 L3 T0] . . . . (2)

And, the dimensional formula of mass = [M1 L0 T0] . . . . (3)

On substituting equation (2) and (3) in equation (1) we get,

Density = Mass × Volume-1

Or, (ρ) = [M1 L0 T0] × [M0 L3 T0]-1 = [M1 L-3 T0]

Therefore, density is dimensionally represented as [M1 L-3 T0].

Hope i helped!
5 0
4 years ago
Read 2 more answers
A wheel rotating with a constant angular acceleration turns through 22 revolutions during a 5 s time interval. Its angular veloc
sesenic [268]

Answer:

0.52rad/s^2

Explanation:

To find the angular acceleration you use the following formula:

\omega^2=\omega_o^2+2\alpha\theta   (1)

w: final angular velocity

wo: initial angular velocity

θ: revolutions

α: angular acceleration

you replace the values of the parameters in (1) and calculate α:

\alpha=\frac{\omega^2-\omega_o^2}{2\theta}

you use that θ=22 rev = 22(2π) = 44π

\alpha=\frac{(12rad/s)^2-(0rad/s)^2}{2(44\pi)}=0.52\frac{rad}{s^2}

hence, the angular acceñeration is 0.52rad/s^2

3 0
3 years ago
Please help!! This is the last question and i’m unsure! I will mark brainliest! Please try to provide a explanation you don’t ha
Flauer [41]

Answer:

True

Explanation:

As of Newton's law, yes. Because when I land my feet on the ground, I apply a force. As per Newton's third law, the ground must apply the same force on me.

If its correct, may I hv brainliest?

7 0
3 years ago
An electric power station is producing 210 kW of power that is to be sent to a small town located 34.0 km away. Each of the two
gladu [14]

You probably know this equation giving the power dissipated:

P = IV

P = power, I = current, V = applied voltage

We can substitute I = V/R from Ohm's law:

P = V²/R

Given values:

V = 30.0×10³V, R = 0.40Ω/km×34.0km = 13.6Ω

Plug in and solve for P:

P = (30.0×10³)²/13.6

P = 6.62×10⁷W

5 0
3 years ago
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