True or false.sliding friction is stronger than static friction

Physics

1 answer:

satela [25.4K]3 years ago

5 0

Static friction is stronger than sliding friction. So your question would be FALSE

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A train travels 63 kilometers in 2 hours, and then 56 kilometers in 3 hours. What is its average speed? i need the answer and un

kolbaska11 [484]

The average speed is the ratio between the total space and the total time of the motion:
$v= \frac{S_{tot}}{t_{tot}}$
The total space is
$S_{tot}=63 km + 56 km = 119 km$
while the total time is
$t_{tot}=2h+3h = 5h$
So, the average velocity is
$v= \frac{119 km}{5 h} =23.8 km/h
$

We can also rewrite it in m/s. The total space is $S_{tot}=119000 m$ , while the time is $t_{tot}=5h\cdot 3600 s/h = 18000s$ , and so
$v= \frac{119000m}{18000s}=6.6 m/s$

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2 years ago

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vladimir2022 [97]

Answer:

true true false true false

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1 year ago

Read 2 more answers

A marble resting near the edge of .90 m high table is given an initial horizontal speed of 1.24 m/s. What will be it’s horizonta

Maru [420]

Answer:

0.53 m

Explanation:

First of all, we have to consider the vertical motion of the ball, in order to find the time it takes for the marble to reach the ground. The initial height is $h=0.90 m$ , the initial vertical velocity is zero, while the acceleration is $g=-9.81 m/s^2$ , so the vertical position at time t is given by

$y(t)=h-\frac{1}{2}gt^2$

By demanding y(t)=0, we find the time t at which the ball reaches the ground:

$0=h-\frac{1}{2}gt^2$

$t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(0.9 m)}{9.81 m/s^2}}=0.43 s$

Now we can find the horizontal range of the marble: we know the initial horizontal speed (v=1.24 m/s), we know the total time of the motion (t=0.43 s), and since the horizontal speed is constant, the total distance traveled on the horizontal direction is

$x=vt=(1.24 m/s)(0.43 s)=0.53 m$