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3 years ago

Magnetic fields exist

Physics

1 answer:

Effectus [21]3 years ago

6 0

Answer:

Magnetic fields exist near a magnet, farther away from a magnet, and within a magnet.

So, the answer is D. All of the above.

Let me know if this helps!

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a wildlife biologist examines for a genetic trait he suspects may be linked to sensitivity to industrial toxins in the environme

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The probability he finds the trait in none of the dogs

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3 years ago

I need some advice I have two girlfriends as of now.

Paul [167]

Answer:

I Would go with Kye.

Explanation:

Why i would go with her is because she has more life experience with you. She also knows you better. I would usually go with the closest one and the one who knows you the best.

Hope this helps.

<3 Have a good day!

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3 years ago

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Where a subducting plate slides beneath the lithosphere, melting takes place and a(n) ____ is created?

11111nata11111 [884]

under ground cave will be created

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3 years ago

Would u rather/content creator or a rap artist

BartSMP [9]

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2 years ago

10. A hockey puck with mass 0.3 kg is sliding along ice that can be considered frictionless. The puck’s velocity is 20 m/s when

SVEN [57.7K]

Answer:

$d = \frac{v^2_i}{2a}= \frac{(20m/s)^2}{2* 3.43 m/s^2}=58.309m$

Explanation:

For this case we can use the second law of Newton given by:

$\sum F = ma$

The friction force on this case is defined as :

$F_f = \mu_k N = \mu_k mg$

Where N represent the normal force, $\mu_k$ the kinetic friction coeffient and a the acceleration.

For this case we can assume that the only force is the friction force and we have:

$F_f = ma$

Replacing the friction force we got:

$\mu_k mg = ma$

We can cancel the mass and we have:

$a = \mu_k g = 0.35 *9.8 \frac{m}{s^2}= 3.43 \frac{m}{s^2}$

And now we can use the following kinematic formula in order to find the distance travelled:

$v^2_f = v^2_i - 2ad$

Assuming the final velocity is 0 we can find the distance like this:

$d = \frac{v^2_i}{2a}= \frac{(20m/s)^2}{2* 3.43 m/s^2}=58.309m$

5 0

3 years ago