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4 years ago

What is the energy of one mole of photons with a wavelength of 418 nm? (h = 6.63 10-34 J . s, N = 6.02 1023.)

Physics

1 answer:

FrozenT [24]4 years ago

8 0

Answer:E = 9.54×10-²Joules

Explanation:

Energy of photon E = hc/¶

Where ¶ is the wavelength

Given h = 6.63×10-³⁴ c= H = 6.02×10²³ ¶ = 418nm = 418 ×10^-9

Substituting the values in the formula

E = 6.63×10-³⁴×6.02×10²³/418 ×10^-9

E = 9.54×10-²Joules

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3 years ago

Read 2 more answers

What is the time constant of a series circuit where the capacitor is 0.330μF and the resistor is 10Ω ?

PtichkaEL [24]

Answer:

$\tau=3.3*10^{-6}s$

Explanation:

Take at look to the picture I attached you, using Kirchhoff's current law we get:

$C*\frac{dV}{dt}+\frac{V}{R}=0$

This is a separable first order differential equation, let's solve it step by step:

Express the equation this way:

$\frac{dV}{V}=-\frac{1}{RC}dt$

integrate both sides, the left side will be integrated from an initial voltage v to a final voltage V, and the right side from an initial time 0 to a final time t:

$\int\limits^V_v {\frac{dV}{V} } =-\int\limits^t_0 {\frac{1}{RC} } \, dt$

Evaluating the integrals:

$ln(\frac{V}{v})=e^{\frac{-t}{RC} }$

natural logarithm to both sides in order to isolate V:

$V(t)=ve^{-\frac{t}{RC} }$

Where the term RC is called time constant and is given by:

$\tau=R*C=10*(0.330*10^{-6})=3.3*10^{-6}s$

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3 years ago