Answer:
The length and the magnification of this telescope are 41 cm and 0.108.
Explanation:
Given that,
Focal length of first lens f= 4.0 cm
Focal length of other lens f'= 37 cm
We need to calculate the length of the telescope
Using formula of length

Put the value into the formula

We need to calculate the magnification of the telescope
Using formula of the magnification

Put the value into the formula


Hence, The length and the magnification of this telescope are 41 cm and 0.108.
(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.
(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.
<h3>Electric field at a point on the Gaussian surface</h3>
The magnitude of the electric field at a point on the cylindrical Gaussian surface is calculated as follows;
E = λ/2πε₀r
where;
- λ is linear charge density
- ε₀ is permitivity of free space
- r is the position of the charge
<h3>At a distance of 5.5 m</h3>

<h3>At a distance of 2.5 m</h3>

Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.
Learn more about electric field here: brainly.com/question/14372859
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