CI2 is the answer to your question
Answer:
C. greater than D, but less than 2D
Explanation:
The amount of potential energy in the system is a function of the compression of the spring. That is the same for both masses.
The potential energy is transferred to kinetic energy when the spring is released. The kinetic energy is jointly proportional to the mass and the square of the velocity. That is, the velocity is inversely proportional to the square root of the mass, for the same kinetic energy.
The horizontal distance traveled will be proportional to the launch velocity. So a halving of the mass will increase the velocity by a factor of ...
v2 = v1·√(1/(1/2)) = v1·√2
This means the second mass will land at a distance of about D√2, a value ...
greater than D but less than 2D.
Answer:

Explanation:
Newton's Law of Universal Gravitation:
- F = force of gravity (N)
- G = gravitational constant

= mass of Object 1 (kg)
= mass of Object 2 (kg)- r = distance between the center of mass (m)
Let's convert our given information to scientific notation:
Now using the gravitational force and the distance between centers of mass that are given, we can plug these into Newton's law:
Remove the units for better readability.
Divide both sides of the equation by the gravitational constant G.
Distribute the power of 2 inside the parentheses.
If we evaluate the left side of the equation, we get:
Multiply both sides of the equation by r.
In order to find the mass of one asteroid, we can use the fact that both asteroids have the same mass, therefore, we can rewrite
as
.
Square root both sides of the equation.
Since m is in units of kg, we can state that the mass of each asteroid is 2.79 * 10⁵ kg.
Answer:
The balloon will move forward.
The density of the air will be greater at the back of the balloon; similar
to the density of air being greater at lower altitudes due to gravitational
attraction because of the weight of the air in an air column.
A block of wood in water rises because of the difference in pressures
on the top and bottom of the block.