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wel
3 years ago
9

Technician A says that vehicle-to-vehicle communication results in fewer traffic collisions. Technician B says there are concern

s related to cybersecurity and a loss of privacy. Which technician is correct?
a) technician A only
b) technician B only
c) both technician A and B
d) neither technician A nor B
Physics
1 answer:
Leto [7]3 years ago
4 0

Answer:

Option C. Both technicians A and B are correct

Explanation:

Vehicle-to-vehicle communications consists of a wireless network where automobiles send messages containing operational information such as speed, location, direction of travel, braking, and loss of stability.

Technician A is correct, there will be fewer traffic collision because each driver will have enough information about traffic flow and such information will be properly managed since they have been known before hand.

By letting out information, such as your location, direction of traffic, etc, there is loss of privacy. This can lead to a security threat on the part of the users

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CI2 is the answer to your question
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4 years ago
A small object of mass M is shot horizontally from a spring launcher that is attached to a table. All frictional forces are cons
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Answer:

  C.  greater than D, but less than 2D

Explanation:

The amount of potential energy in the system is a function of the compression of the spring. That is the same for both masses.

The potential energy is transferred to kinetic energy when the spring is released. The kinetic energy is jointly proportional to the mass and the square of the velocity. That is, the velocity is inversely proportional to the square root of the mass, for the same kinetic energy.

The horizontal distance traveled will be proportional to the launch velocity. So a halving of the mass will increase the velocity by a factor of ...

  v2 = v1·√(1/(1/2)) = v1·√2

This means the second mass will land at a distance of about D√2, a value ...

  greater than D but less than 2D.

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3 years ago
The gravitational force between two asteroids is 2.59 × 10 (exponent)-6 N. The centers of mass are 2000 meters away and their ma
makkiz [27]

Answer:

2.79 \times 10^5 \ \text{kg}

Explanation:

Newton's Law of Universal Gravitation:

  • $F= G\frac{m_1 m_2}{r^2}
  • F = force of gravity (N)
  • G = gravitational constant (6.67 \times 10^-^1^1 \ N\frac{m^2}{kg^2})
  • m_1 = mass of Object 1 (kg)
  • m_2 = mass of Object 2 (kg)
  • r = distance between the center of mass (m)

Let's convert our given information to scientific notation:

  • 2000 \ m \rightarrow 2.0 \times 10^3 \ m

Now using the gravitational force and the distance between centers of mass that are given, we can plug these into Newton's law:

  • 2.59 \times 10^-^6 $\ N = 6.67 \times 10^-^1^1 \ N \frac{m^2}{kg^2}  \times \frac{m_1 m_2}{(2.0 \times 10^3 \ m)^2}

Remove the units for better readability.

  • 2.59 \times 10^-^6=6.67 \times 10^-^1^1 \frac{m_1m_2}{(2.0 \times 10^3)^2}

Divide both sides of the equation by the gravitational constant G.

  • \frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{(2.0 \times 10^3)^2}

Distribute the power of 2 inside the parentheses.

  • \frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{2.0 \times 10^6}

If we evaluate the left side of the equation, we get:

  • 3.88305847 \times 10^4 = \frac{m_1m_2}{2.0 \times 10^6}

Multiply both sides of the equation by r.

  • 7.76611694 \times 10^1^0= m_1m_2

In order to find the mass of one asteroid, we can use the fact that both asteroids have the same mass, therefore, we can rewrite m_1m_2 as m^2.

  • 7.76611694 \times 10^1^0= m^2

Square root both sides of the equation.

  • m=\sqrt{7.76611694 \times 10^1^0}
  • m=2.78677536 \times 10^5
  • m=2.79 \times 10^5

Since m is in units of kg, we can state that the mass of each asteroid is 2.79 * 10⁵ kg.

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Answer:

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