Question

Determine the mass of 1 mol of gold (Au), of aluminum chloride (AlCl3), and of glucose (C6H12O6)

Answer 1

Answer: Mass of 1 mol of gold (Au) is 197g , of aluminum chloride$(AlCl_3)$ is 133.5 g and of glucose $(C_6H_{12}O_6)$ is 180 g

Explanation:  Mass of 1 mole of a substance is called its molar mass.

a) 1 mole of $Au$ contains $6.023\times 10^{23}atoms$ and weigh 197g.

b) 1 mole of $AlCl_3$ will weigh=$1\times {\text {mass of 1 mole of Aluminium}}+3\times {\text {mass of 1 mole of chlorine atom}}$

Thus mass of 1 mole of $AlCl_3$ will be $=1moles\times {27g/mol}+3moles\times {35.5g/mol}=133.5g$

c) 1 mole of $C_6H_{12}O_6$ will weigh=$6\times {\text {mass of 1 mole of carbon}}+12\times {\text {mass of 1 mole of hydrogen atom}}+6\times {\text {mass of 1 mole of oxygen}}$

1 mole of $C_6H_{12}O_6$ will weigh=$6\times 12g/mol+12\times 1g/mol+6\times 16g/mol=180g$