Ask question

Ask question

All categories

Anestetic [448]

3 years ago

12

What can you find using newton's three laws of motion

1 answer:

topjm [15]3 years ago

4 0

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

hope this helps! :)

You might be interested in

marissas car accelerates uniformly at a rate of -2.60m/s^2. how long does it take for marissas car to accelerate from a velocity

zlopas [31]

Answer:

1.02s

Explanation:

In this situation the following equation will be useful:

Where:

is Marissa's car final velocity

is Marissa's car initial velocity

is Marissa's car constant acceleration (assuming this is the acceleration, since 1269 m/s^{2} does not make sense)

is the time it takes to accelerato from to

7 0

2 years ago

Physics please help !!

jeyben [28]

Answer:

(C)

Explanation:

Volume is independent of the mass. Volume depends on the spatial dimensions so no matter how much you change the mass, volume will remain the same.

3 0

2 years ago

Three particles lie in the xy plane. Particle 1 has mass m1 = 6.7 kg and lies on the x-axis at x1 = 4.2 m, y1 = 0. Particle 2 ha

krek1111 [17]

Answer:

$F=18.58\times 10^{-11}\ N$

$\theta=30.276^{\circ}$

Explanation:

Given:

mass of first particle, $m_1=6.7\ kg$

mass of second particle, $m_2=5.1\ kg$

mass of third particle, $m_3=3.7\ kg$

coordinate position of first particle in meters, $(x_1,y_1)\equiv(4.2,0)$

coordinate position of second particle in meters, $(x_2,y_2)\equiv(0,2.8)$

coordinate position of third particle in meters, $(x_3,y_3)\equiv(0,0)$

<u>Now, gravitational force on particle 3 due to particle 1:</u>

$F_{31}=G\frac{m_1.m_3}{r_{31}^2}$

$F_{31}=6.67\times 10^{-11} \times \frac{6.7\times 3.7}{4.2^2}$

$F_{31}=9.37\times 10^{-11}\ N$

towards positive Y axis.

<u>gravitational force on particle 3 due to particle 2:</u>

$F_{32}=G\frac{m_2.m_3}{r_{21}^2}$

$F_{32}=6.67\times 10^{-11} \times \frac{5.1\times 3.7}{2.8^2}$

$F_{32}=16.05\times 10^{-11}\ N$

towards positive X axis.

<u>Now the net force</u>

$F=\sqrt{F_{31}\ ^2+F_{32}\ ^2}$

$F=\sqrt{(10^{-11})^2(9.37^2+16.05^2)}$

$F=18.58\times 10^{-11}\ N$

<em>For angle in counterclockwise direction from the +x-axis</em>

$tan\theta=\frac{9.37\times 10^{-11}}{16.05\times 10^{-11}}$

$\theta=30.276^{\circ}$

4 0

3 years ago

All of the following are environmental factors that affect human development except _____.

MrRa [10]

Answer:

The answer would be....

Explanation:

Chromosomes.

5 0

3 years ago

Why can't you feel rhe force of attraction between you and mars

NISA [10]

Because Mars is too far away for its gravitational pull to affect us, in addition Earths gravitational pull is greater than Mars anyways.

4 0

3 years ago