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laiz [17]
3 years ago
14

Rank the magnitudes of the diffusion coefficients from greatest to least for the following systems:(a) Cr in Fe at 600°C; (b) C

in Fe at 900°C; (c) Cr in Fe at 900°C. Now justify this ranking. You MUST write a short paragraph to explain your ranking
Engineering
2 answers:
lisabon 2012 [21]3 years ago
8 0

Answer:

The rank of the magnitude of diffusion coefficients from greatest to least is as follows:

1) "C" in "Fe" at 900°C

2) "Cr" in "Fe" at 900°C

3) "Cr" in "Fe" at 600°C

Explanation:

"C" in "Fe" is an interstitial impurity while "Cr" in "Fe" is a substitutional impurity".

With that being said, interstitial diffusion occurs in "C" in "Fe" systems while substitutional diffusion occurs in "Cr" in "Fe" systems.

Also, Interstitial diffusion is much faster than substitutional diffusion, hence the order we got in the answer.

Also, with increasing temperature, magnitude of diffusion coefficient increases due to the relation;

D =D° Exp (-Qd/RT)

Where;

D° = temperature independent pre-exponential

Qd = the activation energy for diffusion

R = universal gas constant

T = absolute temperature

jek_recluse [69]3 years ago
3 0

Answer:

Explanation:

The rank of the magnitude of the diffusion coefficient from greatest to least is as follows:

C in Fe at 900°C > Cr in Fe at 900°C > Cr in Fe at 600°C

Reason

C in Fe is an interstitial impurity while Cr in Fe is a substutional impurity.Therefore interstitial impurity occurs in C in Fe systems,while substutitional diffusion occurs in Cr in Fe system.Interstitial is much faster than substitutional diffusion hence the order

Also with increasing temperature magnitude of diffusion coefficient increases,due to the relation.

     D = D₀exp(-Qd/RT)

Where D₀=Temperature independent per exponential

           Qd= The activation energy for diffusion

             R= Universal gas constant

              T=absolute temperature

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Answer:

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b) The minimum acceptable value is 39.4 HRC using Rockwell C hardness test.

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According to DIN 50150, the constant for Rockwell C hardness test is ≈31.5 around this values of tensile strength:

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Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and modifying th
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Answer:

# kelvin_to_celsius function is defined

# it has value_kelvin as argument

def kelvin_to_celsius(value_kelvin):

   # value_celsius is initialized to 0.0

   value_celsius = 0.0

   

   # value_celsius is calculated by

   # subtracting 273.15 from value_kelvin

   value_celsius = value_kelvin - 273.15

   # value_celsius is returned

   return value_celsius

   

# celsius_to_kelvin function is defined

# it has value_celsius as argument

def celsius_to_kelvin(value_celsius):

   # value_kelvin is initialized to 0.0

   value_kelvin = 0.0

   

   # value_kelvin is calculated by

   # adding 273.15 to value_celsius

   value_kelvin = value_celsius + 273.15

   # value_kelvin is returned

   return value_kelvin

   

value_c = 0.0

value_k = 0.0

value_c = 10.0

# value_c = 10.0 is used to test the function celsius_to_kelvin

# the result is displayed

print(value_c, 'C is', celsius_to_kelvin(value_c), 'K')

value_k = 283.15

# value_k = 283.15 is used to test the function kelvin_to_celsius

# the result is displayed

print(value_k, 'is', kelvin_to_celsius(value_k), 'C')

Explanation:

Image of celsius_to_kelvin function used as guideline is attached

Image of program output is attached.

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