Question

Convert the following temperatures to Kelvin:

Answer 1

Explanation:

A. 100°C to Kelvins

$T(K)=T(^oC)+273.15$

$T(K)=100(^oC)+273.15=373.15 K$

B 600°R to Kelvins

$(T)^oK=((T)^oR)\times 1.8$

$(T)^oK=600\times 1.8 K = 1080 K$

C. 98°F to Kelvins

$(T(K)-273.15)=(T(^oF)-32)\times \frac{5}{9}$

$(T(K))=(98(^oF)-32)\times \frac{5}{9}+273.15=309.81K$

D. 77.4°F to degree Celsius

$((T)^oC)=((T)^oF-32)\times \frac{5}{9}$

$(T)^oC =(77.4^oF-32)\times \frac{5}{9}=25.22^oC$

E. 77.4 K to degree Celsius

$T(^oC)=T(^K)-273.15$

$T(^oC)=77.4(K)-273.15=-195.75^oC$

F. 77.4°R to degree Celsius

$(T)^oC=((T)^oR-491.67)\times \frac{5}{9}$

$(T)^oC=((77.4)^oR-491.67)\times \frac{5}{9}=-230.15 ^oC$