Answer:
Molecular formula of aniline is C6H5NH2.
Explanation:
As we know, molecular mass can be calculated as
Molar mass = C6H5NH2
Molar mass = (6*12)+(1*7)+(28)
Molar mass = 93 g/mol
Answer:
714 nm
Explanation:
Using the equation: nλ=d<em>sin</em>θ
where
n= order of maximum
λ= wavelength
d= distance between lines on diffraction grating
θ= angle
n is 1 because the problem states the light forms 1st order bright band
λ is unknown
d= 
or 0.0000014 (meters)
sin(30)= 0.5
so
(1)λ=(0.0000014)(0.5)
=0.000000714m or 714 nm
Answer:
Option ( 1 )
Explanation:
This atom has a cub close pack structure, and therefore - the number of edge center present in X atoms = 4,
Number of unit cells present in X atoms = 6
____________________________________________________
Now the 6th coordination number of X atom = 6 * 4 = 24,
So respectively, the 3rd coordination number of X = 8 -
And thus the ratio between the 6th coordination number and the 3rd coordination number = 24 / 8 = 3,
Option ( 1 )
<u><em>Hope that helps!</em></u>
Answer:
The answer to your question is P2 = 0.78 atm
Explanation:
Data
Temperature 1 = T1 = 263°K Temperature 2 = T2 = 298°K
Volume 1 = V1 = 24 L Volume 2 = V2 = 35 L
Pressure 1 = P1 = 1 Pressure 2 = P2 = ?
Process
1.- To solve this problem use the Combined gas law
P1V1/T1 = P2V2/T2
-Solve for P2
P2 = P1V1T2 / T1V2
-Substitution
P2 = (1)(24)(298) / (263)(35)
-Simplification
P2 = 7152 / 9205
-Result
P2 = 0.777
or P2 = 0.78 atm
The half life of uranium- 238 is
4.46 x10^9 years
Explanation
Half life is the time taken for the radioactivity of a isotope to fall to half its original value.
The original mass of uranium-238 is 4.0 mg
Half of original mass of uranium = 4.0 mg /2 = 2.0 mg
since it take 4.46 x 10^ 9 years for the sample to half the half life of uranium -238 = 4.46 x10^9 years
