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Scorpion4ik [409]
3 years ago
14

When the equation Eg(s) + DnGO4(aq) ---> Dn(s) + Eg2(GO4)3(aq) is balanced, what is the coefficient in

Chemistry
1 answer:
Artemon [7]3 years ago
5 0

B) 2

You would first balance GO4 by adding a coefficient of 3 in front of DnGO4 in the reactants. Then you’d balance the 3DnGO4 by adding a coefficient of 3 in front of Dn in the products. Finally you’d balance Eg by adding a coefficient of 2 in front of Eg to balance with the Eg2(GO4)3 in the products.
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Two molecules of one reactant combine with 3 molecules of another to produce 5 molecules of a product.
maksim [4K]

Answer:

A = 2A + 3B → 5C

Explanation:

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2A + 3B   →   5C

Other options are incorrect because,

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in this reaction one molecule of  A₂ and one molecule of B₃ combine to from one molecule of C₃.

3 0
3 years ago
For the simple decomposition reactionAB(g)→ A(g) + B(g)Rate =k[AB]2 and k=0.2 L/mol*s . How long will it takefor [AB] to reach 1
mixer [17]

Answer:

6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.

Explanation:

Rate = k[AB]^2

The order of the reaction is 2.

Integrated rate law for second order kinetic is:

\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt

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[A_t] is the final concentration  = 1/3 of initial concentration = \frac{1}{3}\times 1.50\ mol/L = 0.5 mol/L

Rate constant, k = 0.2 L/mol*s

Applying in the above equation as:-

\frac{1}{0.5} = \frac{1}{1.50}+0.2t

\frac{1}{1.5}+0.2x=\frac{1}{0.5}

t = 6.66\ s

<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>

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