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LenaWriter [7]
3 years ago
10

3 different levels of fire​

Chemistry
1 answer:
inna [77]3 years ago
6 0

Answer:

Levels of Understanding: “Fire-fighting” at Multiple Levels ... Each night is different, and yet they are all the same. ... 3, No. 7, September 1992). This is consistent with our evolutionary history, which was geared toward responding to immediate ...

Explanation:

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Calculate freeze 62.9 g of iron at 1535oC<br> Hf (J/g)=257
Inessa [10]

Answer:

<u>-16200J</u>

Explanation:

(257J/g)(62.9g)

eliminate the variables

u get 16165.3

go to 3 significant digits

u get 16200

and since it is freezing we are taking out energy so it would be

-16200J

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3 years ago
A material found in air, water, or soil that is harmful to humans or other organisms
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The answer is pollutant
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If the half-life of technitium-104 is 18.0 min, how much of a 14.2-g sample will remain after 72 minutes?
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The decay of a radioactive isotope can be predicted using the formula: A = Ao[2^(-t/T_0.5)] where A is the amount after time t, Ao is the original amount and T_0.5 is the half-life. Using the equation and the given values, 0.888 g of the sample will remain after 72 minutes. 
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Personal eyeglasses provide as much protection as Group of answer choices splash proof chemical goggles a face shield safety gla
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Answer:

none of the above

Explanation:

6 0
3 years ago
A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil
Flura [38]

Answer:  Molarity of Cl^- anions in the chemist's solution is 0.0104 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles  

V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L

Therefore, the molarity of solution will be 5.2\times 10^{-3}mole/L

MgCl_2\rightarrow Mg^{2+}+2Cl^-

As 1 mole of MgCl_2 gives 2 moles of Cl^-

Thus 5.2\times 10^{-3}  moles of MgCl_2 gives =\frac{2}{1}\times 5.2\times 10^{-3}=0.0104

Thus the molarity of Cl^- anions in the chemist's solution is 0.0104 M

6 0
3 years ago
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