a)5m/s b)5
the 5 is because you add the seconds to get 8 seconds and then do the same with the distance to get 40. 40/8 = 5. speed = 5
Velocity = displacement/change in time
V = 40/8
I just realized how unorganised my math looks but I hope this is helpfull
Daniddmelo says it right there, don't know why he got reported.
The potential energy (PE) is mass x height x gravity. So it would be 25 kg x 4 m x 9.8 = 980 joules. The child starts out with 980 joules of potential energy. The kinetic energy (KE) is (1/2) x mass x velocity squared. KE = (1/2) x 25 kg x 5 m/s2 = 312.5 joules. So he ends with 312.5 joules of kinetic energy. The Energy lost to friction = PE - KE. 980- 312.5 = 667.5 joules of energy lost to friction.
Please don't just copy and paste, and thank you Dan cause you practically did it I just... elaborated more? I dunno.
Answer:
Vf = 4.77 m/s
Explanation:
During the downward motion we can easily find the final velocity or the velocity with which the ball hits the ground, by using third equation of motion. The third equation of motion is given as follows:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height = 1.16 m
Vf = Final Velocity of Ball = ?
Vi = Initial Velocity of Ball = 0 m/s (Since, ball was initially at rest)
Therefore, using these values in the equation, we get:
(2)(9.8 m/s²)(1.16 m) = Vf² - (0 m/s)²
Vf = √(22.736 m²/s²)
<u>Vf = 4.77 m/s</u>
Answer:
<em>The number 0.0217 has 3 significant digits</em>
Explanation:
<u>Significant Digits
</u>
These are digits that contribute to the significance of the number. Some rules apply to discard the non-significant digits like:
- Leading zeros
- Trailing zeros (with exceptions)
Our number is 0.0217 has two leading zeros before the 2 because they only occupy space to indicate the order of magnitude of the number. Only the 2,1,7 are significant digits, thus
The number 0.0217 has 3 significant digits
Answer:
This is not a question, but a statement. The concept that the work done is equal to the input work on a simple machine is called ideal machine. An ideal machine has 100% efficiency which means that there is no loss. All the amount of input work is equal to the useful output of the machine.
Explanation:
