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scoundrel [369]
3 years ago
11

Which statements about isomers are true? Check all that apply. (6 pt) a) Enantiomers have the same molecular formula. b) Enantio

mers are not mirror images of each other that can be superimposed. c) In the ranking of functional groups, alcohols rank above carboxylic acids. d) The R-isomer of a molecule shows an optical rotation of -9°. Its enantiomer shows +9°. e) A molecule with three chiral centers can potentially have nine stereoisomers. f) Meso tartaric acid has the same melting point as its diastere
Chemistry
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

a) TRUE

b) FALSE

c) FALSE

d) TRUE

e) FALSE

f) FALSE

Explanation:

a) Enantiomers have the same molecular formula. TRUE. Because defintion of enantiomer is: One of the two molecules that are mirror images of each other and are non-superposable. To be mirror image must have the same molecular formula.

b) Enantiomers are not mirror images of each other that can be superimposed. FALSE. That is the negation of the enantiomer definition.

c) In the ranking of functional groups, alcohols rank above carboxylic acids. FALSE. In Cahn-Ingold-Prelog rules, carbon of carboxylic acid is bonded with two oxygens but in alcohols is bonded with just one oxygen.

d) The R-isomer of a molecule shows an optical rotation of -9°. Its enantiomer shows +9°. TRUE. One way to differentiate R- S-isomers is with optical rotation. The rotation of R-isomer will be the negative of S-isomer

e) A molecule with three chiral centers can potentially have nine stereoisomers. FALSE. The usual number of isomers is 2ⁿ where n is number of chiral centers. With three chiral centers number is stereoisomers is 8.

f) Meso tartaric acid has the same melting point as its diastere. FALSE. Diastereoisomers have different physical and chemical properties.

I hope it helps!

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You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain
Margarita [4]

Answer: 12


Explanation.


This problem was recently posted and deals with the conversion of units,so I give the same answer.


You need to convert the 9 quibs of skvarnick to sleps, to determine how many sleps you have.


The conversion of units is easily undertaken once you build your conversion factors.


Conversion factors are ratios (fractions) equivalent to one, which permits use the identity property of the multiplication to change one unit to a different equivalent one.


Remember that the identity property of multiplication states that any amount multiplied by 1 remains unchanged, i.e.

               a.1=a

Then, build your conversion factor from the definitions given:

  •    12 sleps is equal to 9 quibs.
  •    12 sleps = 9 quibs
  •    in virtue of the division property of equality, you can divide both sides by 12 sleps and get:

                                       1 = 12 sleps /  9 quibs ← conversion factor

Now you can multiply the amount 9 quibs by the conversion factor, which is equal to 1, to find the equivalent amount of sleps:


  •    identity property: 9 quibs = 9 quibs × 1
  •    substitution property: 9 quibs = 9 quibs ×  12 sleps/  9 quibs

You can see that the unit quibs appear in the numerator and the denominator so it cancels out, and the result will be in sleps.


So, all you have to do now is the operations with the numbers:

       9 quibs = (9 ×  12 / 9) sleps = 12 sleps ← answer

3 0
3 years ago
A solid forms when the average energy of a substance's particles
Dahasolnce [82]
<span>Matter is composed of particles that have kinetic energy. Particles with greater kinetic energy tend form liquids or gases due to increased rates of activity of the particles. Particles with lower energy tend to form solids. So, a solid forms when the average energy of a substance's particles decreases.</span>
4 0
3 years ago
A chemist dissolves 699. mg of pure hydrobromic acid in enough water to make up 180. mL of solution. Calculate the pH of the sol
Sedaia [141]

Answer: 1.32

Explanation:

First, we must obtain the molar mass of HBr. After that, we try to obtain the concentration of the hydrobromic acid from the formula n=CV since the volume of solution and mass of acid was provided. Recall that n=m/M. If the concentration of acid is thus obtained, we make use of the fact that the concentration of H+ in the acid is equal to the molar concentration of HBr to obtain the pH. The pH is the negative logarithm of the concentration we obtained in the initial step.

8 0
3 years ago
In a 0.730 M solution, a weak acid is 12.5% dissociated. Calculate Ka of the acid.
Mamont248 [21]

Answer:

Approximately 1.30 \times 10^{-2}, assuming that this acid is monoprotic.

Explanation:

Assume that this acid is monoprotic. Let \rm HA denote this acid.

\rm HA \rightleftharpoons H^{+} + A^{-}.

Initial concentration of \rm HA without any dissociation:

[{\rm HA}] = 0.730\; \rm mol \cdot L^{-1}.

After 12.5\% of that was dissociated, the concentration of both \rm H^{+} and \rm A^{-} (conjugate base of this acid) would become:

12.5\% \times 0.730\; \rm mol \cdot L^{-1} = 0.09125\; \rm mol \cdot L^{-1}.

Concentration of \rm HA in the solution after dissociation:

(1 - 12.5\%) \times 0.730\; \rm mol \cdot L^{-1} = 0.63875\; \rm mol\cdot L^{-1}.

Let [{\rm HA}], [{\rm H}^{+}], and [{\rm A}^{-}] denote the concentration (in \rm mol \cdot L^{-1} or \rm M) of the corresponding species at equilibrium. Calculate the acid dissociation constant K_{\rm a} for \rm HA, under the assumption that this acid is monoprotic:

\begin{aligned}K_{\rm a} &= \frac{[{\rm H}^{+}] \cdot [{\rm A}^{-}]}{[{\rm HA}]} \\ &= \frac{(0.09125\; \rm mol \cdot L^{-1}) \times (0.09125\; \rm mol \cdot L^{-1})}{0.63875\; \rm mol \cdot L^{-1}}\\[0.5em]&\approx 1.30 \times 10^{-2} \end{aligned}.

5 0
3 years ago
Which of the following equations can be used to determine the change in enthalpy of a system? A. `DeltaH_"reaction"=DeltaH_"prod
Nostrana [21]

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]

Hence, the correct answer is Option D.

6 0
3 years ago
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