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3 years ago

If only 10 pounds is required to lift a 500-lb block, how much chain must be played out to lift the engine 3.0 inches?

Physics

1 answer:

adelina 88 [10]3 years ago

3 0

Answer:

150 inches (12.5 ft)

Explanation:

The work done to lift the 500 pound block 3 inches should be the same as that to lift the 10 pond object a given distance.

The following is the equation one needs to solve:

$10 \,lb\,* \,x\,=\,500\,lb\,*\,3\,in\\10 \,lb\,* \,x\,=\,1500\,lb\,in\\$

therefore solving for the distance "x" gives as the answer (in inches):

$10 \,lb\,* \,x\,=\,1500\,lb\,in\\x\,=\,\frac{1500\,lb\,in}{10\,lb} \\\\x\,=150\,in$

which can also be given in feet as: 12.5 ft

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This is a Physics worksheet. please help.

natulia [17]

i think the answer is A

7 0

3 years ago

Red light of wavelength 651 nm produces photoelectrons from a certain photoemissive material. Green light of wavelength 521 nm p

Mnenie [13.5K]

Answer:

material work function is 0.956 eV

Explanation:

given data

red wavelength 651 nm

green wavelength 521 nm

photo electrons = 1.50 × maximum kinetic energy

to find out

material work function

solution

we know by Einstein photo electric equation that is

for red light

h ( c / λr ) = Ф + kinetic energy

for green light

h ( c / λg ) = Ф + 1.50 × kinetic energy

now from both equation put kinetic energy from red to green

h ( c / λg ) = Ф + 1.50 × (h ( c / λr ) - Ф)

Ф =( hc / 0.50) × ( 1.50/ λr - 1/ λg)

put all value

Ф =( 6.63 × $10^{-34}$ (3 × $10^{8}$ ) / 0.50) × ( 1.50/ λr - 1/ λg)

Ф =( 6.63 × $10^{-34}$ (3 × $10^{8}$ ) / 0.50 ) × ( 1.50/ 651× $10^{-9}$ - 1/ 521 × $10^{-9}$ )

Ф = 1.5305 × $10^{-19}$ J × ( 1ev / 1.6 × $10^{-19}$ J )

Ф = 0.956 eV

material work function is 0.956 eV

4 0

3 years ago

Read 2 more answers

What visible wavelengths of light are strongly reflected from a 390-nm-thick soap bubble?

DiKsa [7]

Answer:

So visible wavelength which is possible here is

416 nm and 693.3 nm

Explanation:

As we know that for normal incidence of light the path difference of the reflected ray is given as

$2\mu t + \frac{\lambda}{2} = \Delta x$

so here we can say that for maximum intensity condition we will have

$\Delta x = N\lambda$

so we have

$2\mu t + \frac{\lambda}{2} = N\lambda$

now for visible wavelength we have

for N = 1

$2\mu t = \frac{\lambda}{2}$

$\lambda = 4\mu t$

$\lambda = 4(\frac{4}{3})(390 nm)$

$\lambda = 2080 nm$

for N = 2

$\lambda = \frac{4\mu t}{3}$

$\lambda = \frac{4(\frac{4}{3})(390 nm)}{3}$

$\lambda = 693.3 nm$

for N = 3

$\lambda = \frac{4\mu t}{5}$

$\lambda = \frac{4(\frac{4}{3})(390 nm)}{5}$

$\lambda = 416 nm$

6 0

4 years ago

What is not an example of absorption ?

blsea [12.9K]

-- water shooting out of a hose

-- writing an email

-- making hard-boiled eggs

-- driving to the dentist

-- the emission spectrum of a carbon arc

-- buying a new car

-- putting your shoes on

-- singing a song

-- cutting a tree down

-- learning to dance

-- cleaning the windows

-- building a radio

-- ironing your shirt

-- riding a bicycle

-- playing the piano

3 0

3 years ago

A wire with a circular cross section and a resistance R is lengthened to 9.66 times its original length by pulling it through a

damaskus [11]

Answer:

The resistance of the wire after it is stretched is 93.31R.

Explanation:

Resistance is the property of the material to oppose the current flow through it. It is given by the relation :

R = (ρl)/A

Here ρ is resistivity, l is length of wire and A is the area of the wire.

Let l₀, and A₀ are the original length and original circular cross section area of the wire. while l₁ and A₁ are the new length and new circular cross section area of the wire.

Volume of the original wire, V₀ = A₀ x l₀

Volume of the new wire, V₁ = A₁ x l₁

According to the problem. volume remain same. So,

V₀ = V₁

A₀ x l₀ = A₁ x l₁

It is given that l₁ = 9.66 x l₀. Substitute this value in the above equation;

A₀ x l₀ = A₁ x 9.66 x l₀

A₁ = A₀/9.66

Resistance of the original wire, R = (ρl₀)/A₀

Resistance of the new wire, R₁ = (ρl₁)/A₁

Substitute the value of l₁ and A₁ in the above equation.

R₁ = (ρ x l₀ x 9.66)/(A₀/9.66) = 93.31 x (ρl₀)/A₀

But (ρl₀)/A₀ = R. hence,

R₁ = 93.31 R

8 0

3 years ago