Answer:
B. Remains constant throughout the flight
Explanation:
If we completely neglect air resistance then the projectile will not have any horizontal resistances to deal with, therefore the horizontal component will remain constant throughout the flight. This would continue to be the case until it meets some form of resistance. Which assuming that everything else is normal would be the case since the force of gravity will push the projectile down (vertical component) until it hits the ground which in that instance would act as an opposing force to the horizontal component as well.
Answer:
Store chemical energy and transfer it to electrical energy when a circuit is connected.
Explanation:
A battery (single cell) is a container made of one cell that can produce a particular amount of electrical energy when needed.
It works by converting chemical energy to electric energy which is then used as a power source.
It stores up chemical energy and when connected to an external circuit, it provides electrical energy (through the flow of electrical current) to the circuit.
A battery is usually made up of a positive electrode and a negative electrode.
Answer:
Potential Difference = 14 V
Explanation:
We are told that when the capacitor plates are charged to a certain voltage, then we have;
ΔV = 14 volts
Now, the battery is disconnected, so here we have the potential difference between the plates to be given by the formula;
ΔV = Q/C
Now, the charge is conserved on the plates and the capacitance is constant, therefore in this case, the potential difference will remain the same.
Thus;
Potential Difference = 14 V
Satellites would be able to detect fires when they start and allow human monitors to review the information and issue warnings.
Answer:
a. I = 0.76 A
b. Z = 150.74
c. RL₁ = 34.41 , RL₂ = 602.58
d. RL₂ = 602.58
Explanation:
V₁ = 116 V , R₁ = 77.0 Ω , Vc = 364 V , Rc = 473 Ω
a.
Using law of Ohm
V = I * R
I = Vc / Rc = 364 V / 473 Ω
I = 0.76 A
b.
The impedance of the circuit in this case the resistance, capacitance and inductor
V = I * Z
Z = V / I
Z = 116 v / 0.76 A
Z = 150.74
c.
The reactance of the inductor can be find using
Z² = R² + (RL² - Rc²)
Solve to RL'
RL = Rc (+ / -) √ ( Z² - R²)
RL = 473 (+ / -) √ 150.74² 77.0²
RL = 473 (+ / -) (129.58)
RL₁ = 34.41 , RL₂ = 602.58
d.
The higher value have the less angular frequency
RL₂ = 602.58
ω = 1 / √L*C
ω = 1 / √ 602.58 * 473
f = 285.02 Hz
