Answer:
we got time and velocity over time.
so the distance is again the area underneath the graph
for a triangle with known base and height it's
4*10 / 2
distance traveled is 20
deceleration occurs when velocity decreases. that happens from t=2 till t=4
in 2 time-units we loose 10 units of velocity, so we decelerate by 5 units per 1 time
a (from t=2 to t=4) = -5v/t
speed = 86km/hr
= 86000/3600
= 23.889m/s
time = 4.6s
acceleration = 23.889/4.6
a = 5.19m/s^2
Answer:
Total height (s) = 176.4 m
Explanation:
Given:
Initial velocity (u) = 0 m/s
Time taken (t) = 6 sec
Acceleration due to gravity = 9.8 m/s²
Find:
Total height (s)
Computation:
s = ut + [1/2]gt²
s = (0)(6) + [1/2][9.8][6²]
s = 176.4 m
Total height (s) = 176.4 m