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Irina18 [472]
3 years ago
5

What is the correct classification of a mixture in which both a solid and liquid are visible?

Chemistry
1 answer:
Setler [38]3 years ago
6 0

The answer is D.

"a heterogeneous mixture and a suspension"

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Find the no. of atoms present in 40g of nitrogen gas at STP?
nika2105 [10]

Answer:

8.60 * 10^{23} atoms N2

Explanation:

We want to convert grams to moles and then moles to atoms.

First, we convert grams of nitrogen gas (which is N2) to moles. To do so, we need the molar mass of N2, which is just 14.01 * 2 = 28.02 g.

40 g N2 * \frac{1 mol N2}{28.02 g N2} = 1.43 mol N2

Now, we need to convert moles to atoms by using Avogadro's number, which is 6.022*10^{23}:

1.43 mol N2 * \frac{6.022*10^{23} atoms N2 }{1 mol N2} = 8.60 * 10^{23} atoms N2

Thus, the answer is 8.60 * 10^{23} atoms N2.

6 0
3 years ago
The K w for water at 0 ∘ C is 0.12 × 10 − 14 M 2 . Calculate the pH of a neutral aqueous solution at 0 ∘ C . p H = Is a pH = 7.2
Karo-lina-s [1.5K]

Answer:

pH → 7.46

Explanation:

We begin with the autoionization of water. This equilibrium reaction is:

2H₂O  ⇄   H₃O⁺  +  OH⁻            Kw = 1×10⁻¹⁴         at 25°C

Kw = [H₃O⁺] . [OH⁻]

We do not consider [H₂O] in the expression for the constant.

[H₃O⁺] = [OH⁻] = √1×10⁻¹⁴   →  1×10⁻⁷ M

Kw depends on the temperature

0.12×10⁻¹⁴ = [H₃O⁺] . [OH⁻]  → [H₃O⁺] = [OH⁻]         at 0°C

√0.12×10⁻¹⁴ = [H₃O⁺] → 3.46×10⁻⁸ M

- log [H₃O⁺] = pH

pH = - log 3.46×10⁻⁸ → 7.46

8 0
3 years ago
Look at the image shown. What does this image represent?
JulijaS [17]

Answer:

Linear molecule with two domains

Explanation:

8 0
3 years ago
There are 20 different amino acids what makes one amino acid different
insens350 [35]
Amino acids carry two functional groups: an amine group (-NH2) and a carboxylic acid group (-COOH). They are different because they have different side chains (R groups) attached to an alpha carbon that is specific to each amino acid.
8 0
3 years ago
eleanor purchased $2568 worth of stock and paid her broker a 0.5% fee. She sold the stock when the stock price increased to 3928
Mrrafil [7]

Answer: $1338.16

Explanation: Total cost of stock= $2568

Total cost of stock including the brokerage =2568+\frac{0.5}{100}\times {2568}=2580.84$

Selling price of stock = $3928

Selling price of stock including trading fee=($3928-$7)=$3919

Net Proceeds = Net selling price of stock - Cost Price of stock

Net Proceeds = ($3919 - $2580.84) = $1338.16


5 0
3 years ago
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