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Irina18 [472]
3 years ago
5

What is the correct classification of a mixture in which both a solid and liquid are visible?

Chemistry
1 answer:
Setler [38]3 years ago
6 0

The answer is D.

"a heterogeneous mixture and a suspension"

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Please comment if you are sure about your answer . Thank you
ryzh [129]
2,3,7,10,13 i did this yesterday can u mark me brainliest

3 0
4 years ago
Write the action of monohydroxy benzene with aqueous bromine​
Romashka-Z-Leto [24]

The reaction yields the product compound 2,4,5-tribromophenol.

<h3>Bromination of monohydroxy benzene</h3>

Bromination is an organic reaction in which aqueous bromine is made to react with another compound so as to introduce bromine into the molecule.

When we carry out the bromination of monohydroxy benzene, we obtain the compound 2,4,5-tribromophenol.

Learn more about benzene: brainly.com/question/14525517

5 0
3 years ago
Calculate the number of moles of C2H6 in 6.29×1023 molecules of C2H6.
Kipish [7]

1.05moles

Explanation:

Given parameters:

Number of molecules of C₂H₆ = 6.29 x 10²³molecules

Unknown:

Number of moles = ?

Solution:

The mole is the amount of substances that contains Avogadro's number of particles i.e 6.02 x 10²³

 To find the number of moles:

  number of moles = \frac{number of particles}{Avogadro's number}

  number of moles = \frac{6.29 x 10^{23} }{6.02 x 10^{23} }

  number of moles = 1.05moles

Learn more:

moles brainly.com/question/1841136

#learnwithBrainly

7 0
3 years ago
Can someone give me an example of balancing equations with a solution that is simple?​
Monica [59]

Explanation:

H _{2}O _{2(aq)} →H _{2}O _{(l)}  + O _{2}(g) \\ solution  : 2 \:  and\: 2

6 0
3 years ago
Read 2 more answers
C2h4 3 o2 2 co2 2 h2o
Marat540 [252]
Use the question marck Moles of CO2
The the giving = 0.624 mol O2
Find the CF faction = 1 mole=  32.00 of O2

O= 2x16.00= 32.00amu ( writte this in the cf fraction)
SET UP THE CHART
Always start with the giving

0.624 mol O2    /  1mol of CO2
___________  / _____________ = Cancel the queal ( O2)
                       / 32.00c O2
                      /
                     /
Multiply the top and divide by the bottom 
0.624 mol CO x 1mol CO2 = 0.624 divide by 32.00 O2 =0.0195
You should look at the giving number ( how many num u gor ever there) 
Ur answer should have the same # as ur givin so 
= 0.0195 
= .0195 mol of CO2
3 0
3 years ago
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