Which one is the strongest acid? •Formic acid •oleic acid •Malnoic acid •None

katrin2010 [14]

Answer:

its not cear to answer this question

6 0

3 years ago

What is the definition of an atmosphere? a portion of the electromagnetic spectrum that makes the sky look blue the blanket of g

goldenfox [79]

Answer:

the blanket of gases that surrounds Earth and some other planets

Explanation:

The best definition of the atmosphere is that it is a portion of the earth that is a made up of a blanket of gases.

The atmosphere is not peculiar to the earth alone, some other planets also have atmospheric cover.
The earth's atmosphere is divided into many different layers.
The weather we see and experience on the earth surface is conditioned within the troposphere.
This troposphere is the closest layer to the surface.

7 0

3 years ago

Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?

chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234 would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now we start with 150 grams of Thorium-234

$150 \times \frac{1}{2}=24.1$

$75 \times \frac{1}{2} =48.2$

$34.5 \times \frac{1}{2} =72.3$

$17.25 \times \frac{1}{2} =96.4$

$8.625\times \frac{1}{2} =120.5$

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

$A=A_{0} \cdot \frac{1}{2^{n}}$

Where

$A_0$ is the initial sample amount

n = the number of half-lives that pass in a given period of time.

7 0

3 years ago

How many atoms are in a sample of 68.7 g copper (Cu)?

dlinn [17]

Divide the number of grams present in the sample by copper's gram atomic weight to find the number of gram atomic weights present. Then multiply that result by Avogadro's Number: 6.022137 x 10^23 atoms/gram atomic weight.1,200 g/(63.54 g/gram atomic weight) ? 18.885741 gram-atomic weights. Hope this helps.

8 0

4 years ago

Read 2 more answers

Can someone please help? This is super hard!!

dezoksy [38]

Answer:

what is super hard?

Explanation:

what?

6 0

2 years ago