Answer:
Explanation: Weight of space probes on earth is given by:
W= weight of the object( in N)
m= mass of the object (in kg)
g=acceleration due to gravity(9.81 
)
Therefore,
Similarly,
Now, considering these two parts as uniform spherical objects
Also, according to Superposition principle, gravitational net force experienced by an object is sum of all individual forces on the object.
Force between these two objects is given by:
G= gravitational constant (
)
= masses of the object
R= distance between their centres (in m)(18 m)
Substituiting all these values into the above formula
This is the magnitude of force experienced by each part in the direction towards the other part, i.e the gravitational force is attractive in nature.
Answer:
= 391.67 Hz
Explanation:
The sound of lowest frequency which is produced by a vibrating sting is called its fundamental frequency ().
The For a vibrating string, the fundamental frequency () can be determined by:
= 
Where v is the speed of waves of the string, and L is the length of the string.
L = 42.0 cm = 0.42 m
v = 329 m/s
= 
= 
= 391.6667 Hz
The fundamental frequency of the string is 391.67 Hz.
Balanced. They’re equally as strong so as their arm wrestling, neither of the men’s hands go down. Because they’re equally/balanced as strong.
Answer:
m = 95000 kg
Explanation:
Given that,
Net force acting on the house, F = 2850 N
Initial speed, u = 0
Final speed, v = 15 cm/s = 0.15 m/s
We need to find the mass of the house. Let the mass be m. We know that the net force is given by :
F = ma
Where
a is the acceleration of the house.
So,
So, the mass of the house is equal to 95000 kg.
