Question

How many grams of phosphorus are in 500.0 grams of calcium phosphide? (i need the work also)

Answer 1

Answer:

$\boxed{\text{170.0 g P}}$ 

Explanation:

The formula of calcium nitride is Ca₃P₂.

The masses of each element are:

$\begin{array}{lrcr}\text{3Ca:} & 3 \times 40.08&=& \text{120.24 u}\\\text{2P:} & 2\times 30.97&=& \text{61.94 u}\\& \text{TOTAL} & = & \text{182.18 u}\\\end{array}$

So, there are 61.94 g of P in 182.18 g of Ca₃P₂.

In 500 g of Ca₃P₂:

$\text{Mass of P} = \text{500.0 g Ca _{3} P _{2} } \times \dfrac{\text{61.94 g P}}{\text{182.18 g Ca _{3} P _{2} }} = \text{170.0 g P}$

There are $\boxed{\textbf{170.0 g P}}$ in 500.0 g of Ca₃P₂.