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ExtremeBDS [4]
3 years ago
5

or a particular reaction, Δ H ∘ = − 16.1 kJ and Δ S ∘ = − 21.8 J/K. Assuming these values change very little with temperature, a

t what temperature does the reaction change from nonspontaneous to spontaneous?
Chemistry
1 answer:
Inessa [10]3 years ago
3 0

Answer:

Reaction is non-spontaneous when T > 738.5K and spontaneous when T < 738.5K

Explanation:

A reaction is non-spontaneous when ΔG° > 0 and is spontaneous when ΔG° < 0

ΔG° is defined as:

ΔG° = ΔH° - TΔS°

ΔG° will be > 0 (non-spontaneous) when  ΔH° > TΔS° and vice versa. Thus:

-16100J > T × -21.8J/K

738.5K > T

That means the reaction is <em>non-spontaneous when T > 738.5K and spontaneous when T < 738.5K</em>

I hope it helps!

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