The atomic mass of K is 39
from Avogadro's law
39g of K contains 6.02x10^23 atoms
therefore if
39=6.02x19^23
X=5.11×10^22
making X the subject of the formula
X= (5.11×10^22×39)÷6.02×10^23
X= 33g
The answer is
C. Control reaction rate
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Answer:
The number of chlorine atoms present in
units of gold III chloride is
Explanation:
Formula of Gold (III) chloride: 
<em>Avogadro Number</em> : Number of particles present in <u>one mole</u><u> </u>of a substance.
Using,


= 1 mole(0.9999 , nearly equal to 1 )
The given Gold III chloride sample is 1 mole in amount.
= 1 mole of 
In this Sample,
1 mole of
will give = 3 mole of Chlorine atoms
1 mole of Cl contain =
3 mole of Cl contain = 
3 mole of Cl contain =
So,
The number of chlorine atoms present in
units of gold III chloride is