Answer:
Net force = 250 N
Explanation:
Given that,
The mass of a teacher, m = 75 kg
As the parachute opens, the system experiences a 1000N drag.
We need to find the magnitude of net force acting on the teacher. 2 forces are acting on her i.e. drag force and weight.
Net force,
F = mg-D
= 75(10)-1000
= -250 N
Hence, the net force is 250 N and it is acting in the upward direction.
I would say that there shouldn't be any calls on a plane while in-flight because you never know what someone is calling for. It can lead to a bad situation like 9/11 or any form of terrorism.
Answer:
c=326.5177 J/kg.K
Specific heat is c=326.5177 J/kg.K
Explanation:
In order ti find the specific heat, we will proceed as follow:
Formula we are going to use is:
Where:
Q is the heat energy added
m is the mass of sample
c is the specific heat
is the temperature Rise.
First we will find the mass:
Weight=m*g (g is gravitational acceleration=9.8 m/s^2)
Rearranging above formula:
c=326.5177 J/kg.K
Specific heat is c=326.5177 J/kg.K
The difference between true north and magnetic north is called "declination."
The magnitude of the object's velocity is
√ (5.1² + 2.82²) = √ (33.9624) = 5.828 m/s .
Kinetic energy = (1/2) (M) (speed²)
= (1/2) (5.22 kg) (5.828 m/s)²
= (2.61 kg) (33.9624 m²/s²)
= 88.64 kg-m²/s²
= 88.64 Joules
