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lawyer [7]
2 years ago
5

Okay okay two questions heh

Physics
2 answers:
tensa zangetsu [6.8K]2 years ago
3 0
The answer for question 2 i guess it’s c
wariber [46]2 years ago
3 0
Electric fan I believe
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Technician A says that the pushrods should be rotating while the engine is running if the camshaft and lifters are okay. Technic
Karo-lina-s [1.5K]

Answer:

Technician A

Explanation:

camshafts rotate at one-half the crankshaft speed

6 0
3 years ago
The length of a cylindrical axon is 8 cm and its radius of 8μm,and the thickness of the membrane is 0.01μm,dielectric constant (
GuDViN [60]

Answer:

9.965 nF

Explanation:

The capacitance of the axon C = εA/d where ε = dielectric constant = 24.78 × 10⁻¹² F/m, A = surface area of axon = 2πrL where r = radius of axon = 8 μm = 8 × 10⁻⁶ m and L = length of axon = 8 cm = 8 × 10⁻² m and d = thickness of membrane = 0.01 μm = 0.01 × 10⁻⁶ m

So, C = εA/d

C = ε2πrL/d

Substituting the of the values variables into the equation, we have

C = ε2πrL/d

C =  24.78 × 10⁻¹² F/m × 2π × 8 × 10⁻⁶ m × 8 × 10⁻² m/0.01 × 10⁻⁶ m

C =  9964.63 × 10⁻²⁰ Fm/0.01 × 10⁻⁶ m

C =  996463 × 10⁻¹⁴ F

C = 9.96463 × 10⁻⁹ F

C = 9.96463 nF

C ≅ 9.965 nF

6 0
3 years ago
A 615.00 kg race car is uniformly traveling around a circular race track. It takes the race car 20.00 seconds to do one lap arou
koban [17]

Answer:

The value is  f  =  0.05 \ Hz

Explanation:

From the question we are told that

     The mass of the car is  m  =  615 \  kg

      The period of the circular motion is  T  =  20 \  s

      The radius  is r =  80 \  m/s

Generally the frequency of the circular motion is  

       f  =   \frac{1}{T }

=>    f  =   \frac{1}{ 20  }

=>    f  =  0.05 \ Hz

3 0
3 years ago
Once juno reaches jupiter, what is the minimum amount of time it takes for the transmitted signals to travel from the spacecraft
Komok [63]

In very very very round figures . . .

-- Jupiter is about 5.2 times as far from the sun as the earth is.

-- So when Jupiter and the EARTH are aligned in both orbits, Jupiter is about

(4.2) x (150 million kilometers) = 630 million kilometers

Time = (distance) / (speed)

The speed of light and radio is 300,000 km/second

Time = (630 million / 300 thousand)

<em>Time = 2,100 seconds</em>

That's 35 minutes.

4 0
3 years ago
Read 2 more answers
1.Mention two uses of the concave mirror.
Anuta_ua [19.1K]

Answer:

1. telescope

2.

f =  \frac{r}{2}

f =  \frac{r}{2}f- focal length

f =  \frac{r}{2}f- focal length r- the radius of curvature of the mirror

\frac{1}{f}  =   \frac{1}{p}  +  \frac{1}{l}

p-the distance of the object from the vertex of the mirror

l-the distance of the figure from the vertex of the mirror

8 0
3 years ago
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