Answer:
a

b
Explanation:
From the question we are told that
The radius of the flywheel is 
The mass of the flywheel is 
The rotational speed of the flywheel is 
The power supplied by the motor is 
Generally the moment of inertia of the flywheel is mathematically represented as

substituting values


The kinetic energy that is been stored is

substituting values

Generally power is mathematically represented as

=> 
substituting the value

The answer to number 1 is D and the answer for the second one is 2
^-^
How are we suppose to answer this tho?
The bus will travel a further 20 m before coming to rest.
<h3>What is acceleration?</h3>
The term acceleration has to do with a change in velocity with time. Now we have;
u = 20 m/s
v = 10 m/s
s = 60 m
Now;
v^2 = u^2 -2as
v^2 - u^2 = -2as
(10)^2 - (20)^2 = - 2 * a * 60
a = (10)^2 - (20)^2/ - 2 * 60
a = 100 - 400/ - 2 * 60
a = 2.5 m/s^2
At that time;
v = 0 m/s
u = 20 m/s
a = 2.5 m/s^2
s = ?
Hence;
u^2 = 2as
s = u^2/2a
s = (20)^2/ 2 * 2.5
s = 400/5
s = 80 m
Hence, the bus will travel a further 20 m before coming to rest.
Learn more about acceleration:brainly.com/question/12550364
#SPJ1
Answer: (2) 108 C
Explanation:
Electric charge of 1 coulomb has said to have passed when a current of 1 Ampere is passed for 1 second.

Q= charge in coloumb = ?
I = current in amperes = 0.120 A
t= time in seconds = 900 sec
